Question

Manuel kicks a can horizontally off the edge of the sidewalk into the street of 10m/s. The curb is .15 meters tall

Answer 1

Time taken to reach the ground is given by vertical direction

$y = v_y * t + \frac{1}{2}gt^2$

$0.15 = 0 + \frac{1}{2}*9.8*t^2$

$t = 0.175 s$

now in the same time it will move horizontally

$d = v_x * t$

$d = 10 * 0.175 = 1.75 m$

so it will land at distance 1.75 m