Answer:
a. v = 4748.42 m/s
b. mass = 10.32 * 10⁻²⁶kg
Explanation:
Electric field, E = 151 V/m
Magnetic field , B =3.18×10⁻²T
(a)
When the ion emerges from the velocity selector, its velocity is :
v = E / B................(1)
= (151 V/m) / (3.18×10 ⁻² T)
velocity, v = 4748.42 m/s
(b)
Magnetic field B =1.75×10⁻² T
radius of the path of the ions r = 17.5 cm = 0.175 m
magnetic force, F = Bvq ................... (1)
Applying Newton's second law of motion ,
Force F = ma
here , centripetal acceleration a = v2/r
force F = mv2/r ................ (2)
comparing equations (1) & (2) , we have,
Bvq = mv2/r
Bq = mv/r
mass, m = Bqr/v
= (1.75×10⁻² T)(1.6*10⁻¹⁹ C)(0.175 m) /(4748.42 m/s)
mass = 10.32 * 10⁻²⁶kg