In order to recreate the process of energy
1 answer:
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Answer:
v₀ₓ = 28.6 m / s
Explanation:
This is a missile throwing exercise
y = t - ½ g t²
as the dart is thrown horizontally the vertical velocity is zero (I go = 0)
y = - ½ g t²
t =
let's calculate
t =
t = 0.175 s
the expression for horizontal displacement is
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 5.00 / 0.175
v₀ₓ = 28.6 m / s
Answer:
(a) burnout speed at apogee in the external tank disposal orbit=7.82 km/sec
(b) ΔV required for the OMS-1 =0.066 km/sec
(c) ΔV required for the OMS-2 =0.045 km/sec
(d) This part of the question is explained in detailed way in the attached file.
Explanation:
Detailed explanation of all the parts of the question are given in attached files.
