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NNADVOKAT [17]
3 years ago
9

__________________ refers to the average increase in the Earth's temperature, which causes changes in climate.

Physics
1 answer:
Mamont248 [21]3 years ago
5 0
Greenhouse effect = CO2 emissions in the air causing rising temperature causing global warming and climate changes
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Who sided with the French
Step2247 [10]

The French were helped by the Hurons

5 0
3 years ago
Read 2 more answers
A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3.0 m is initially at rest. A 20 kg boy approaches the m
nekit [7.7K]

Answer:

The velocity of the merry-go-round after the boy hops on the merry-go-round is 1.5 m/s

Explanation:

The rotational inertia of the merry-go-round = 600 kg·m²

The radius of the merry-go-round = 3.0 m

The mass of the boy = 20 kg

The speed with which the boy approaches the merry-go-round = 5.0 m/s

F_T \cdot r = I \cdot \alpha  = m \cdot r^2  \cdot \alpha

Where;

F_T = The tangential force

I =  The rotational inertia

m = The mass

α = The angular acceleration

r = The radius of the merry-go-round

For the merry go round, we have;

I_m \cdot \alpha_m  = I_m \cdot \dfrac{v_m}{r \cdot t}

I_m = The rotational inertia of the merry-go-round

\alpha _m = The angular acceleration of the merry-go-round

v _m = The linear velocity of the merry-go-round

t = The time of motion

For the boy, we have;

I_b \cdot \alpha_b  = m_b \cdot r^2  \cdot \dfrac{v_b}{r \cdot t}

Where;

I_b = The rotational inertia of the boy

\alpha _b = The angular acceleration of the boy

v _b = The linear velocity of the boy

t = The time of motion

When the boy jumps on the merry-go-round, we have;

I_m \cdot \dfrac{v_m}{r \cdot t} = m_b \cdot r^2  \cdot \dfrac{v_b}{r \cdot t}

Which gives;

v_m = \dfrac{m_b \cdot r^2  \cdot \dfrac{v_b}{r \cdot t} \cdot r \cdot t}{I_m} = \dfrac{m_b \cdot r^2  \cdot v_b}{I_m}

From which we have;

v_m =  \dfrac{20 \times 3^2  \times 5}{600} =  1.5

The velocity of the merry-go-round, v_m, after the boy hops on the merry-go-round = 1.5 m/s.

5 0
3 years ago
A 70.0-kilogram man is walking at a speed if 2.0 m/s. What is the kinetic energy?
Paraphin [41]

Answer:

140 J

Explanation:

From the the question, the mass of the man =70.0 kg and the speed at which the man is walking =2.0 m/s.

K.E =  \frac{1}{2}m {v}^{2}

where K.E = the kinetic energy, m=mass and v= speed.

By substitution,

K.E =  \frac{1}{2} \times 70 \times  {2}^{2}

\implies \: K.E = \frac{280}{2}

\implies K.E =140

Hence the kinetic energy of the man is 140J

3 0
3 years ago
Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes th
aev [14]

Answer:

A) G = m³/kg.s²

B) E = kg.m²/s²

Explanation:

A)

The given relation is:

F = Gm₁m₂/r²

where, the units of all variables are:

F = Force = kg.m/s²

m₁ = m₂ = mass = kg

r = distance = m

G = Gravitational Constant = ?

Therefore,

kg.m/s² = G(kg)(kg)/m²

(kg.m/s²)(m²/kg²) = G

<u>G = m³/kg.s²</u>

<u></u>

B)

The given equation is:

E = mc²

where, the units of all variables are:

m = mass = kg

c = speed = m/s

E = Energy = ?

Therefore,

E = (kg)(m/s)²

<u>E = kg.m²/s²</u>

This is the correct answer, which is not present in any option.

4 0
4 years ago
I need help with this pls
enyata [817]
Friction makes a moving object slower
8 0
3 years ago
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