For the given problem, we calculate the required time by
using the formula P = W/t.
P = [(1/2)mv_f^2 – (1/2)mv_i^2]/ t
The car accelerates from 0 -58 mph, so the power engine will
be
P = (1/2) x m x 58^2 / t = 1682 m / t
According to the problem, the engine produces full power so
the time required can be calculated as
420.5 m / 1.40 = 1682 m / t
t = 5.6 seconds
To solve this problem it is necessary to apply Boyle's law in which it is specified that
Where,
and 
are the initial pressure and volume values
and 
are the final pressure volume values
The final pressure here is the atmosphere, then
Pressure at the water is given by,
Using Boyle equation we have,
Therefore the volume of the lungs at the surface is 5.9L
Answer:
v2=0.79 m/s
Explanation:
equation of continuity: V1A1=V2A2
A=(pi)r^2
A1=(pi)(0.55cm)^2
A2=(pi)(1.17cm)^2
convert cm2->m2
A1= 0.95cm2=
A2= 4.3cm2=
(3.57 m/s)(0.000095 m^2)=(x m/s)(0.00043 m^2)
v2=0.79 m/s
hope this helped
Answer:
9.17 m/s
Explanation:
Impulse = change in momentum
FΔt = mΔv
(166 N) (0.39 s) = (7.06 kg) Δv
Δv = 9.17 m/s
W = F x d
F: 450 N
d = 10 m
plug your variables into the equation to get W = 450N x 10m
