Using the Sine rule,
![\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BLet%20A%20%3D%2014m%2C%7D%20%5C%5C%20Substituting%20the%20variables%20into%20the%20formula%2C%3Cp%3EWhere%20the%20length%20of%20the%20wires%20are%2C%20AP%20%3D%20xm%20and%20BP%20%3D%20ym%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%5Csin80%5E0%7D%7B14%7D%3D%5Cfrac%7B%5Csin40%5E0%7D%7Bx%7D%20%5C%5C%20%5Ctext%7BCrossmultiply%2C%7D%20%5C%5C%20x%5Ctimes%5Csin%2080%5E0%3D14%5Ctimes%5Csin%2040%5E0%20%5C%5C%20Divide%5Ctext%7B%20both%20sides%20by%20%7D%5Csin%2080%5E0%20%5C%5C%20x%3D%5Cfrac%7B14%5Csin40%5E0%7D%7B%5Csin80%5E0%7D%20%5C%5C%20x%3D9.14m%20%5Cend%7Bgathered%7D)
Hence, the length of wire AP (x) is 9.14m.
For wire BP (y)m,
Sum of angles in a triangle is 180 degrees,
Using the side rule to find the length of wire BP,
Hence, the length of wire BP (y) is 12.31m
Therefore, the length of the wires are (9.14m and 12.31m).
Answer:
Eddie used the incorrect ratio for sin
Step-by-step explanation:
sinT = 
= 
= 
, then
∠ T = 
( )
Answer:
I hope it's helpful for you
Answer:
C.) False, counterexample of 15
1) 15 is divisible by 3 but not by 6
we know that 15 = 3*5 or 15/3=5, So 15 IS DIVISIBLE BY 3
BUT 15/6=2.5 THIS PROVES 15 IS NOT PERFECTLY DIVISIBLE BY 6
2) 12= 3*4 & 6*2
SO 12 IS PERFECTLY DIVISIBLE BY 3 & 6 BUT 15 IS NOT. THUS THE ANSWER IS 'C'
Create an equation. Since all of the angles of any triangle add up to 180 degrees, our equation will be:
7x+25+9x+25+5x+25=180.
Now, jus solve for x.
Combine like terms
21x+75=180
Subtract 75 on both sides to further simplify.
21x=105
Finally, divide both sides by 21 to isolate x.
X=5
Hope this helps!
