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3 years ago

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A company offers premium cable for 39.95 per month plus a one time setup fee. the total cost for setup and 6 monthes of service

is 264.70.
a.write an equation in point slope form to find the total price y for any number of monthes x.(hint:the point (6,264.70)is a solution to the equation.)
b.write the equation in slope intercept form.
c.what is the setup fee?

1 answer:

Yakvenalex [24]3 years ago

8 0

Answer:

Part a) The equation of the line in point slope form is

$y-264.70=39.95(x-6)$

Part b) The equation in slope intercept form is

$y=39.95x+25$

Part c) The setup fee is $25

Step-by-step explanation:

Part a) write an equation in point slope form

Let

x ------> the number of months of service

y -----> the total cost

we know that

The equation of the line in point slope form is

$y-y1=m(x-x1)$

where

m is the slope

(x1,y1) is a point that lie on the line

In this problem we have that the cost of $39.95 per month is equal to the rate or slope of the linear equation

$m=39.95\ \frac{\$}{month}$

we have that the point (6,264.70) is a solution of the linear equation

substitute the given values

$y-264.70=39.95(x-6)$ ----> equation in point slope form

Part b) write the equation in slope intercept form

The equation of the line on slope intercept form is

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

we have

$y-264.70=39.95(x-6)$

Isolate the variable y

Distribute right side

$y-264.70=39.95x-239.70$

Adds 264.70 both sides

$y=39.95x-239.70+264.70$

$y=39.95x+25$

Part c) what is the setup fee?

The setup fee is the y-intercept of the linear equation

The y-intercept is the value of y when the value of x is equal to zero

In this problem, the y-intercept is the total cost when the number of months of service is equal to zero (the cost is equal to the setup fee)

For x=0

$y=39.95(0)+25$

$y=\$25$

The setup fee is $25

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