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TEA [102]
3 years ago
15

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

ulation variance. Round your answer to three decimal places. 1.04,1.00,1.13,1.08,1.11
Mathematics
1 answer:
Helen [10]3 years ago
3 0

Answer:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

But we need to calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_I}{n}

And replacing we got:

\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072

And for the sample variance we have:

s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance \sigma^2

E(s^2) = \sigma^2

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

But we need to calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_I}{n}

And replacing we got:

\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072

And for the sample variance we have:

s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance \sigma^2

E(s^2) = \sigma^2

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You work at a pioneer historical site. On this site you have handcarts. One cart has a handle that connects to the center of the
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Answer:

a)  see below

b)  radius = 16.4 in (1 d.p.)

c)  18°. Yes contents will remain. No, handle will not rest on the ground.

d)  Yes contents would spill.  Max height of handle = 32.8 in (1 d.p.)

Step-by-step explanation:

<u>Part a</u>

A chord is a <u>line segment</u> with endpoints on the <u>circumference</u> of the circle.  

The diameter is a <u>chord</u> that passes through the center of a circle.

Therefore, the spokes passing through the center of the wheel are congruent chords.

The spokes on the wheel represent the radii of the circle.  Spokes on a wheel are usually evenly spaced, therefore the congruent central angles are the angles formed when two spokes meet at the center of the wheel.

<u>Part b</u>

The <u>tangent</u> of a circle is always <u>perpendicular</u> to the <u>radius</u>.

The tangent to the wheel touches the wheel at point B on the diagram.  The radius is at a right angle to this tangent.  Therefore, we can model this as a right triangle and use the <u>tan trigonometric ratio</u> to calculate the radius of the wheel (see attached diagram 1).

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = 20°
  • O = radius (r)
  • A = 45 in

Substituting the given values into the tan trig ratio:

\implies \sf \tan(20^{\circ})=\dfrac{r}{45}

\implies \sf r=45\tan(20^{\circ})

\implies \sf r=16.37866054...

Therefore, the radius is 16.4 in (1 d.p.).

<u>Part c</u>

The measure of an angle formed by a secant and a tangent from a point outside the circle is <u>half the difference</u> of the measures of the <u>intercepted arcs</u>.

If the measure of the arc AB was changed to 72°, then the other intercepted arc would be 180° - 72° = 108° (since AC is the diameter).

\implies \sf new\: angle=\dfrac{108^{\circ}-72^{\circ}}{2}=18^{\circ}

As the handle of the cart needs to be no more than 20° with the ground for the contents not to spill out, the contents will remain in the handcart at an angle of 18°.

The handle will not rest of the ground (see attached diagram 2).

<u>Part d</u>

This can be modeled as a right triangle (see diagram 3), with:

  • height = (48 - r) in
  • hypotenuse ≈ 48 in

Use the sin trig ratio to find the angle the handle makes with the horizontal:

\implies \sf \sin (\theta)=\dfrac{O}{H}

\implies \sf \sin (\theta)=\dfrac{48-r}{48}

\implies \sf \sin (\theta)=\dfrac{48-45\tan(20^{\circ})}{48}

\implies \theta = 41.2^{\circ}\:\sf(1\:d.p.)

As 41.2° > 20° the contents will spill out the back.

To find the <u>maximum height</u> of the handle from the ground before the contents start spilling out, find the <u>height from center of the wheel</u> (setting the angle to its maximum of 20°):

\implies \sin(20^{\circ})=\dfrac{h}{48}

\implies h=48\sin(20^{\circ})

Then add it to the radius:

\implies \sf max\:height=48\sin(20^{\circ})+45\tan(20^{\circ})=32.8\:in\:(1\:d.p.)

(see diagram 4)

------------------------------------------------------------------------------------------

<u>Circle Theorem vocabulary</u>

<u>Secant</u>: a straight line that intersects a circle at two points.

<u>Arc</u>: the curve between two points on the circumference of a circle

<u>Intercepted arc</u>: the curve between the two points where two chords or line segments (that meet at one point on the other side of the circle) intercept the circumference of a circle.

<u>Tangent</u>: a straight line that touches a circle at only one point.

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A bookshop had 650 copies of a book for sale. The books were marked at 75 per copy in order to make a profit of 30%. A bookselle
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Answer:

The percentage profit of the bookshop will make on the whole is 27%.

Step-by-step explanation:

The following are given in the question:

Copies of books for sale = 650

Selling price per copy = 75

Copies sold at 5% discount = 300

Discount rate = 5%, or 0.05

Percentage profit per copy = 30%, or 0.30

To calculate cost per copy, the following formula is used:

Percentage profit per copy = (Selling price per copy – Cost per copy) / Cost per copy …….. (1)

Substituting the values into equation (1) and solve for Cost per copy, we have:

30% = (75 - Cost per copy) / Cost per copy

0.30 * Cost per copy = 75 - Cost per copy

(0.30 * Cost per copy) + Cost per copy = 75

1.30 * Cost per copy = 75

Cost per copy = 75 / 1.30

Cost per copy = 57.6923076923077

Therefore, we have:

Total cost = Copies of books for sale * Cost per copy = 650 * 57.6923076923077 = 37,500

Selling price at 5% discount = 75 * (100% - Discount rate) = 75 * (100% - 5%) = 75 * 95% = 71.25

Revenue from sales at selling price at 5% discount = Selling price at 5% discount * Number of sales at 5% discount = 71.25 * 300 = 21,375

Revenue from the remaining copies sold at 75 per copy = (Copies of books for sale - 300) * 75 = (650 - 300) * 75 = 350 * 75 = 26,250

Total revenue = Revenue from sales at selling price at 5% discount + Revenue from sales at 75 per copy = 21,375 + 26,250 = 47,625

Total profit = Total revenue - Total cost = 47,625 - 37,500 = 10,125

To calculate the percentage profit of the bookshop will make on the whole, the following formula is used:

Percentage profit on the whole = (Total profit / Total cost) * 100 ................ (2)

Substituting the relevant values form above into equation (2), we have:

Percentage profit on the whole = (10,125 / 37,500) * 100

Percentage profit on the whole = 0.27 * 100

Percentage profit on the whole = 27%

Therefore, the percentage profit of the bookshop will make on the whole is 27%.

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