The last answer
the place where the organisms live
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Answer:
During the prophase of mitosis, the chromatin in a cell compacts to form condensed chromosomes; this condensation is required in order for the cell to divide properly. While mitotic cells have condensed chromosomes, interphase cells do not.
Explanation:
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Answer: 50.7 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of 
![\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3Dmolarity%5Ctimes%20%7B%5Ctext%20%7BVolume%20in%20L%5D%7D%3D0.417M%5Ctimes%200.528L%3D0.220moles)
The balanced chemical equation is:
is the limiting reagent as it limits the formation of product and 
is in excess.
According to stoichiometry :
2 moles of give = 1 mole of 
Thus 0.220 moles of give=
of
Mass of 
Thus 50.7 g of will be formed.
For #3 the answer is B, for #4 the answer is F, and for #5 the answer is B.
Answer:
The answer to your question is AgCl
Explanation:
Data
Silver = Ag = 75%
Chlorine = Cl = 25%
1.- Convert percent numbers to grams
Silver = 75 g
Chlorine = 25 g
2.- Calculate the moles of each element
Mass number Ag = 108 g
Mass number Cl = 35.5 g
108 g of Ag ------------------ 1 mol
75 g of Ag ------------------ x
x = (75 x 1) / 108
x = 75 / 108
x = 0.69 moles
35.5 g of Cl ------------------ 1 mol
25 g of Cl ----------------- x
x = (25 x 1) / 35.5
x = 0.70 moles
3.- Divide by the lowest number of moles
Ag = 0.69/0.69 = 1
Cl = 0.70 / 0.69 = 1.02 ≈ 1
4.- Write the empirical formula
Ag₁ Cl₁ = AgCl
