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Usimov [2.4K]
2 years ago
6

Which of the following is not a way populations are described?​

Chemistry
2 answers:
gladu [14]2 years ago
4 0
The last answer

the place where the organisms live

Hope this helps!!! :))))
Ipatiy [6.2K]2 years ago
3 0
<h3>Hello There ! </h3>

• Which of the following is not a way populations are described ?

<h3>Answer:- </h3>

0 ✓ ) The places where the organisms live .

<h3>___________________________</h3>

• Four characteristics to describe populations are geographic range, density and distribution, growth rate, and age structure .

• A population is defined as a group of individuals of the same species living and interbreeding within a given area.

• Scientists study a population by examining how individuals in that population interact with each other and how the population as a whole interacts with its environment.

<h3>Hope this helps you...! </h3>
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How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and
il63 [147K]

Answer:

How the relative density of a substance is related to the density calculate the density of iron if its relative density is 2 and a density of water is 2gcm -3

R.d= relative density of substance/ relative density of water

R.d= 2/2

R.d= 1gcm-3

Explanation:

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3 years ago
Which electron in sulfur is most shielded from nuclear charge?
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Answer: 3p Orbitals

Explanation:

Electrons present in the 3p orbitals are farthest from the nucleus. Therefore, the electrons present in the 3p orbital will be shielded by the electrons present in the inner orbitals. Hence, 3p orbital in sulfur is most shielded from the nuclear charge".

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2 years ago
"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"
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Answer:- The Ka for the acid is 1.53*10^-^5 .

Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

Now, we make the ice table for this equation as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

I 0.25 0 0

C -X +X +X

E (0.25 - X) X X

where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.

X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.

Ka = [H^+][A^-]\frac{1}{HA}

Where, Ka is the acid ionization constant. Let's plug in the values.

Ka = \frac{X^2}{0.25-X}

Let's calculate the value of X first using the equation:

pH = -log[H^+][/tex]

on taking antilog ob above equation we get:

[H^+]=10^-^p^H

[H^+]=10^-^2^.^7^1

[H^+] = 0.00195

So, X = 0.001195

Let's plug in this value of X in the equation:-

Ka=\frac{(0.00195)^2}{0.25-0.00195}

Ka=1.53*10^-^5

So, the value of Ka for butyric acid is 1.53*10^-^5 .

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3 years ago
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