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S_A_V [24]
2 years ago
12

The heat change that accompanies the formation of 1.00 mol of carbon dioxide from its elements is −393.7 kJ/mol. What heat chang

e accompanies the formation of 0.631 mol CO2?
Chemistry
1 answer:
gladu [14]2 years ago
7 0

Answer:

-248.425 kJ/mol

Explanation:

This question can be done by simply taking the ratios:

Since the given the heat change for 1.00 mol of CO_2 is -373.7 KJ/mol. Let us consider the required Heat Exchange at 0.631 mol of

We can write:

\frac{-373.7} {1.00} = \frac{x}{0.631}

x = ( -373.7)(0.631)

x = -248.425 KJ/mol

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JulsSmile [24]

Since the reaction shown in the question is an acid - base reaction in the Lewis sense; the Lewis acid here is AlCl3  while the Lewis base here is Cl^- .

<h3>What is  a Lewis acid?</h3>

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Now consider the given reaction; AlCl3 +Cl^- ------> AlCl 4 ^-. The Lewis acid here is AlCl3  while the Lewis base here is Cl^- .

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3 years ago
A gas sample occupies 3.25 liters at 297.5K and 2.4 atm. Determine the temperature at which the gas will occupy 4.25 L at 1.50 a
lorasvet [3.4K]

For equal moles of  gas, temperature can be calculated from ideal gas equation as follows:

P×V=n×R×T ...... (1)

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2.4 atm ×3.25 L=n×R×297.5 K

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3 years ago
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B. released, forming bonds usually releases energy.
6 0
2 years ago
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In this way, your reasoning is correct and it is probably a mistake in the book.

6 0
3 years ago
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