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3 years ago

What is the magnification of a virtual image if the image is 60.0 cm from a

Physics

2 answers:

guajiro [1.7K]3 years ago

8 0

Answer: 4.0

Explanation:

Hatshy [7]3 years ago

6 0

Answer:

4cm

Explanation:

Magnification of the virtual image

= image distance / object distance

Given

Image distance = 60.0cm

Object distance = 15.0cm

Therefore,

Magnification = 60.0/15.0

= 4 cm

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How much energy (in kW-h) does a 900 Watt stove use in a week if it is used for 1.5 hours each day?

ioda

Answer:

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Explanation:

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3 years ago

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ludmilkaskok [199]

Answer:

a. water

Explanation:

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So, the correct option is:

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2 years ago

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A 50 kg pitcher throws a baseball with a mass of 0.15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is

Andreas93 [3]

The velocity of the pitcher is 0.105 m/s in a direction opposite to the velocity of the ball.

When no external force acts on a system, the total momentum of the system is conserved. The total initial momentum of the system is equal to the total final momentum of the system.

The pitcher and the ball are initially at rest, therefore, the total initial momentum of the system is zero.

Since no external forces act on the system comprising of pitcher and the ball, the total final momentum of the system is also equal to zero.

If the mass of the pitcher is mp and its speed is vp, the mass of the ball is mb and the ball's speed is vb, then the final momentum of the system of pitcher and the ball is given by,

$p=m_pv_p+m_bv_b=0$

Therefore,

$v_p=-\frac{m_b}{m_p} v_p$

Substituet 0.15 kg for mb, 50 kg for mp and 35 m/s for vb.

$v_p=-\frac{m_b}{m_p} v_p=-\frac{0.15 kg}{50 kg} (35m/s)=-0.105 m/s$

The pitcher has a velocity 0.105 m/s opposite to the direction of the velocity of the ball.

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3 years ago

How many cm3 are there in 1 dm3?

Verdich [7]

The answer is in the picture.

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2 years ago

Slow-twitch muscles are needed for what?

Tresset [83]

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3 years ago

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