Pythagorean Therom
a^2 + b^2 = c^2
5^2 +b^2 = 7^2
25=b^2 = 49
49-25=b^2
49-25=14
b^2=24
b=sqrt24
sqrt24=4.89898
I assume you mean the product of mixed numbers,
3 1/2 × 3 1/2
If we write this as
(3 + 1/2) × (3 + 1/2) = (3 + 1/2)²
we can use the identity
(a + b)² = a² + 2ab + b²
so that
3 1/2 × 3 1/2 = 3² + (2 × 3 × 1/2) + (1/2)²
3 1/2 × 3 1/2 = 9 + 3 + 1/4
3 1/2 × 3 1/2 = 12 1/4
Alternatively, we can first write 3 1/2 as a mixed number:
3 + 1/2 = 6/2 + 1/2 = (6 + 1)/2 = 7/2
Then
3 1/2 × 3 1/2 = 7/2 × 7/2 = (7 × 7) / (2 × 2) = 49/4
and
49/4 = (48 + 1)/4 = ((4 × 12) + 1)/4 = 12 + 1/4
Answer:
76
Step-by-step explanation:
recall that for a quadratic equation in the form
ax² + bx + c = 0, the discriminant is given by
discriminant, D = b²- 4ac
we are given the following:
-6x² + 2x + 3 = 0,
comparing this with the general equation above, it is clear that,
a = -6, b = 2 and c = 3,
substituting these into our equation for discriminant:
D = b²- 4ac
= 2² - 4(-6)(3)
= 4 + 72
= 76
Answer:
area if sector= teeta. ×πr²
360
<u>120</u>°. ×<u>2</u><u>2</u>×9×9
360. 7
<u>3×1782</u>
7
5346
