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sweet-ann [11.9K]
3 years ago
8

43% of 300 is what number

Mathematics
1 answer:
Stells [14]3 years ago
8 0
129
Find 10% (30) then times by 4 to find 40% (120)
Find 1% (3) then times by 3 to find 3% (9)
Add the 40% to the 3% (120 + 9)
= 129
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Is 91.7% rational or irrational​
nadezda [96]

Answer: Hi! 91.7% is a rational number. Because...

Step-by-step explanation: rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number. Hope this helps!

3 0
2 years ago
12) Which polynomial function has a leading coefficient of 2, root-5 with multiplicity 3, and root 12 with multiplicity 1?
gogolik [260]

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A

Step-by-step explanation:

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2 years ago
Emery borrowed money from her brother to buy a new phone, and is paying off a fixed amount each week. After 2 weeks, she will ow
jarptica [38.1K]

Answer: A. The original price was $608. B. $76 each week C. Quite useful, as it keeps track of the amount of money she still needs to owe each week.

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5 0
2 years ago
19. Find the value of X (In the picture) (giving points to best answer/brainlest)​
Tema [17]

Answer:

x = 61 degrees

Step-by-step explanation:

The triangle on the right is isosceles and the base angles are congruent

the sum of the inner angles of a triangle is 180 degrees

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y = 32 degrees

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7 0
3 years ago
Plz with steps .. it's very hard can anyone plz
liubo4ka [24]

Answer:

Step-by-step explanation:

\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a}  \qquad  f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a}  \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}}  }{\dfrac{1}{2\sqrt{x}} }\\\\

\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}  =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\

7 0
2 years ago
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