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Irina-Kira [14]
3 years ago
5

the diameter of a can is 8cm the height is 12cm work out how much water is in the can using method V = PI r2h. use 3 as the vaul

e of PI
Mathematics
1 answer:
givi [52]3 years ago
7 0
<span> high and the </span>diameter<span> is </span>8cm using<span> the formula </span>V<span>=.π r ²h, </span>work out<span> how </span>much<span> ...the </span>height<span> h is given as </span>12 cm<span> ... Note: Generally we would </span>use<span> 3.14 as the rounded </span>value<span> of </span>pi<span>. ... when dealing </span>with<span> liquids, turn cm</span>3<span> to milliliters. ... Adding and Subtracting Polynomials Math Word Problem Solution </span>Method<span> ..</span>
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What is the circumference if the diameter is 21in and pi is 22/7
Ede4ka [16]

Answer:

66 in

Explanation:

the circumference can be calculated as:

C=d\cdot\pi

Where d is the diameter and π is 22/7.

So, replacing the values, we get:

C=21\cdot\frac{22}{7}=\frac{21\cdot22}{7}=\frac{462}{7}=66\text{ in}

Therefore, the circumference is 66 in.

6 0
2 years ago
Please solve the worksheet. (factoring trinomials)
Vesnalui [34]

Answer:

1. (x+3)(x+1)

2. (m+4)(m+8)

3. (r-2)(r-1)

4. (x-5)(x-1)

5. (x-7)(x-3)

6. (x-11)(x-11)

7. (t-6)(t+2)

8. (p-8)(p-8)

9. (x-1)(x-9)

10. (x+5)(x+1)

11. (a+9)(a-1)

12. (y-8)(y+1)

13. (x-3)(x+1)

14. (y+13)(y+1)

15. (m+5)(m+4)

16. (x+10)(x+2)

17. (a-12)(a-2)

18. (y+9)(y+2)

19. xy(x+2+y) i think

20. ab(a-4+4b)

21. xy(x+6-7y)

5 0
4 years ago
Write a set of directions for dividing 3.6 by 0.25. Then find the quotient.
Damm [24]
Dividing 3.6 by 0.25 follows the following generic approach : You have to firstly need to multiply both divisor and dividend by that number such that the divisor becomes a whole number first .

So we multiply both dividend and divisor by 100 such that the problem converts to 3.6*100/0.25*100 = 360 being divided by 25 .

So the approach to divide a number froma decimal number is to first convert problem into dividing the number from a whole number , by multiplying both the number and divisor from the approriate number . Which was in above problem comes out to be 100 .
8 0
3 years ago
Given two dependent random samples with the following results:
skad [1K]

Answer:

We Fail to reject Null Hypothesis.

Step-by-step explanation:

We are given two dependent random samples;

Population 1   Population 2   d = Population 1 entry-Population 2 entry    d^{2}

      52                       61                                52 - 61 = -9                                 81

      81                        71                                 81 - 71 = 10                                 100

      72                        82                                72 - 82 = -10                             100

      67                        62                                67 - 62 = 5                                25

      73                        79                                 73 - 79 = -6                               36

      73                        77                                 73 - 77 = -4                                16

      76                        71                                  76 - 71 = 5                                 25

      83                        85                                 83 - 85 = -2                          <u>     4    </u>

                                                                                                              ∑d^{2} <u>= 387                                  </u>

Now,  Null Hypothesis, H_0 : \mu_1 = \mu_2    or   \mu_d = 0

 Alternate Hypothesis, H_1 : \mu_1 \neq  \mu_2     or   \mu_d \neq  0

The test statistics for paired data is given by;

                   \frac{dbar - \mu_d}{\frac{s_d}{\sqrt{n} } } follows t_n_-_1

 where, dbar = Mean of Population 2 data - Mean of Population 1 data

Mean of Population 1 data = \frac{52+81+72+67+73+73+76+83}{8} = 72.125

Mean of Population 2 data = \frac{61+71+82+62+79+77+71+85}{8} = 73.5

 Hence, dbar = 73.5 - 72.125 = 1.375

s_d = Standard Deviation of paired data = \sqrt{\frac{\sum d^{2} - n*(dbar)^{2}  }{n-1} } = \sqrt{\frac{387 - 8*(1.375)^{2}  }{8-1} }

                                                                 = 7.3

n = no. of observations = 8

 So, <em>Test Statistics = </em>\frac{1.375 - 0}{\frac{7.3}{\sqrt{8} } }<em> follows </em>t_7<em> </em>

<em>                          = 0.533</em>

Now, if the critical value of t at 7 degree of freedom is less than the test statistics then we will reject null hypothesis.

At 0.01 level of significance, the t table gives a critical value of 3.499. Since our test statistics is less than the critical value we will not reject null hypothesis and conclude that there is no significant difference between the two population means.

                                                                                                       

                                                                                                     

                                                                                                 

                                                                                                       

                                                                                                 

                                                                                                       

                                                                                                   

                                                                                               

6 0
4 years ago
Use the simple interest formula to find the interest earned and the ending balance. I = Prt
Mkey [24]

Answer:

                   

Step-by-step explanation:

   

4 0
3 years ago
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