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Irina-Kira [14]
3 years ago
5

the diameter of a can is 8cm the height is 12cm work out how much water is in the can using method V = PI r2h. use 3 as the vaul

e of PI
Mathematics
1 answer:
givi [52]3 years ago
7 0
<span> high and the </span>diameter<span> is </span>8cm using<span> the formula </span>V<span>=.π r ²h, </span>work out<span> how </span>much<span> ...the </span>height<span> h is given as </span>12 cm<span> ... Note: Generally we would </span>use<span> 3.14 as the rounded </span>value<span> of </span>pi<span>. ... when dealing </span>with<span> liquids, turn cm</span>3<span> to milliliters. ... Adding and Subtracting Polynomials Math Word Problem Solution </span>Method<span> ..</span>
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You need a length and width for it
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3 years ago
Evaluate the following functions at x = 10<br>g(x)=√(x+1)​
V125BC [204]

g(x)=√(x+1)

Let's plug 10 in for x

g(10) = √(10+1)

Simplify the exponents

g(10) = √(11)

This is the exact form but it can also be expressed as a decimal.

√(11) = 3.31662479

You can simplify as needed

6 0
3 years ago
Read 2 more answers
Find the volume of the composite solid. Round your answer to the nearest tenth
Vesna [10]

Answer:

V = 1206.3 ft^{3}

Step-by-step explanation:

This shape is made up of a cylinder on the bottom and a cone on the top. We'll find the volumes of these shapes separately and then add them together.

Volume of a cylinder = area (of the base) x height

Substitute in the formula for the area of a circle.

V(cylinder) = \pir^{2} x h

Substitute in the values for the radius (8) and height (4)

V(cylinder) = \pi x 8^{2} x 4

Evaluate using a calculator

V(cylinder) = 804.2477

To the nearest tenth, V(cylinder) = 804.2

Volume of a cone = \frac{\pi r^{2}h }{3}. This is the area of the circular part of the cone (\pi r^{2}), multiplied by the height from the point to the base, all divided by 3.

Substitute in the values for the radius of the circle (8) and the height (6)

V(cone) = \frac{\pi 8^{2} 6 }{3} (On the top it's \pi x 8^{2} x 6)

Evaluate using a calculator

V(cone) = 402.1239

To the nearest tenth, V(cone) = 402.1

Total volume = V(cylinder) + V(cone)

= 804.2 + 402.1

= 1206.3 ft^{3}

7 0
3 years ago
Solve the system: 10x-9y=8 21y+15x=0.5
artcher [175]

Answer:

x = 1/2 y = -1/3

Step-by-step explanation:

Split it into 2 equations:

10x-9y=8

and

21y+15x=0.5

10x - 9y = 8

Step 1: Divide both sides by 10:

x = (8+9y)/(10)

Substitute x = (8+9y)/(10) into 21y+15x=0.5 :

21y + (3(8+9))/(2) = 0.5

Solve for y

<u>y= -1/3</u>

Substitute y= -1/3 into x = (8+9y)/(10)

<u>x = 1/2</u>

<u />

3 0
3 years ago
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
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