Answer:
D
Explanation:
This sentence has the most sensory details or details giving more description of the 5 senses.
Hope this helps :)
Answer:
A. Na₂SO₄ and HCl
C. Polar solutes are soluble in polar solvents but are insoluble in non-polar solvents Non-polar solutes are insoluble in polar solvents but are are soluble in non-polar solvents
Ionic solutes are soluble in polar solvents but are insoluble in non-polar solvents.
Like dissolves like simply means that molecules of substances having similar chemical properties dissolve in each other
Explanation:
A. Ionic substances like Na₂SO₄ are composed of charged particles called ions. These ions are either positively charged or negatively charged, therefore, they are attracted to substances of opposite charges. Also, polar molecules like HCl contains two oppositely charged ends. A polar solvent consists of molecules with two oppositely charged ends, therefore, ionic substances as well polar substances dissolve in them according to the concept of like dissolves like.
Gasoline being non-polar will only dissolve in like substances, polar solvents.
C. Polar solutes are soluble in polar solvents but are insoluble in non-polar solvents Non-polar solutes are insoluble in polar solvents but are are soluble in non-polar solvents
Ionic solutes are soluble in polar solvents but are insoluble in non-polar solvents.
The statement "Like dissolves like" simply means that molecules of substances having similar chemical properties dissolve in each other. For example gasoline, a non-polar substance will dissolve only in a non-polar solvent like kerosene. Also, HCl, a polar molecule will dissolve in a polar solvent like water.
Explanation:
Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.
Answer:
237.8L of water would need to be added.
Explanation:
The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).
Then figure out what information you have and what is being found. In this case:
M1 = 54.7 M
V1 = 1092 mL = 1.092 L
M2 = 0.25 M
V2 = unknown
Then solve the equation for whatever you are trying to find.
M1V1=M2V2
V2=M1V1/M2
Now you need to plug everything in.
V2=(54.7M*1.091L)/0.25M
V2=238.93L
That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.
238.93L - 1.091L = 237.8L
Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.
I hope this helps. Let me know if anything is unclear.
