Answer:
A. Protein disulfide is oxidized.
Explanation:
When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.
Answer:
The pH is 13,00 and the solution is basic.
Explanation:
<em> </em>The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and higher than 7 to 14 basic. It is calculated as
pH = -log (H 30+)
Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:
[H3O ^ +]x [OH ^ -] = 1x 10 ^ -14
[H3O ^ +]x [1.0 10-1]=1x 10 ^ -14
[H3O ^ +]= 1x 10 ^ -14/1.0 10-1M= <em>1.0 10-13 M</em>
pH = -log (H 30+)= -log (1.0 10-13 M)= <em>13, 00</em>
As the pH value is higher than 7, it corresponds to a basic substance.
Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol
Answer:
The vertical line indicating bonds breaking
Explanation:
M IS A LETTER but N is a letter
