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aliya0001 [1]
3 years ago
13

A runner accelerates from 0 m/s to 3 m/s in 12 s. What was the acceleration?

Chemistry
1 answer:
german3 years ago
3 0
A=3/12=0.25 m/s²
acceleration is 0.25 m/s²
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A hydrogen-filled balloon was ignited and 2.10 g of hydrogen reacted with 16.8 g of oxygen. How many grams of water vapor were f
stiks02 [169]
Hydrogen + oxygen --> water
2,1g + 16,8g = x
x = 18,9g
5 0
3 years ago
Consider the following intermediate reactions.
Alja [10]

2.1648 kg of CH4 will generate 119341 KJ of energy.

Explanation:

Write down the values given in the question

CH4(g) +2 O2 → CO2(g) +2 H20 (g)

ΔH1 = - 802 kJ

2 H2O(g)→2 H2O(I)

ΔH2= -88 kJ

The overall chemical reaction is

CH4 (g)+2 O2(g)→CO2(g)+2 H2O (I) ΔH2= -890 kJ

CH4 +2 O2 → CO2 +2 H20

(1mol)+(2mol)→(1mol+2mol)

Methane (CH4) = 16 gm/mol

oxygen (O2) =32 gm/mol

Here 1 mol CH4 ang 2mol of O2 gives 1mol of CO2 and 2 mol of 2 H2O

which generate 882 KJ /mol

Therefore to produce 119341 KJ of energy

119341/882 = 135.3 mol

to produce 119341 KJ of energy, 135.3 mol of CH4 and 270.6 mol of O2 will require

=135.3 *16

=2164.8 gm

=2.1648 kg of CH4

2.1648 kg of CH4 will generate 119341 KJ of energy

4 0
3 years ago
Read 2 more answers
Which of these best explains the formation of deep ocean currents
timurjin [86]

Answer:

if you could copy and paste the text or a picture of the options, i'd be more than happy to answer

Explanation:

:)

5 0
2 years ago
How many moles of glucose are produced? <br><br><br><br> How many moles of oxygen are produced?
frozen [14]

Explanation:

5.00 mol H2O × (1 mol C6H12O6/6 mol H2O)

= 0.833 mol C6H12O6

5.00 mol H2O × (6 mol O2/6 mol H2O)

= 5.00 mol O2

6 0
3 years ago
A sample of a mineral solid weighing 28.5 g was added to a graduated cylinder filled with to a level of 20.3 mL. As a result, th
bonufazy [111]

Answer:

2.8 g/mL is the density of the mineral.

Explanation:

The mass, m=28.5\ g

Volume of the object = Volume of water level rose - Initial volume of water = 30.5 mL - 20.3 mL = 10.2 mL

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

\rho=\frac{28.5\ g}{10.2 mL}=2.8\ g/mL

<u>2.8 g/mL is the density of the mineral.</u>

8 0
3 years ago
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