In 1 molecule of the compound C₆H₁₂O₂ there are 12 moles of hydrogen atoms
<h3>Further explanation</h3>
Given
C₆H₁₂O₂ compound
Required
moles of Hydrogen
Solution
In a compound, there is a mole ratio of the constituent elements.
The empirical formula is the smallest comparison of atoms of compound forming elements.
A molecular formula is a formula that shows the number of atomic elements that make up a compound.
In the C₆H₁₂O₂ compound, there are 3 forming elements: C, H and O
The number of each element is indicated by its subscript
C: 6 moles
H = 12 moles
O = 2 moles
Answer:
320 g
Step-by-step explanation:
The half-life of Co-63 (5.3 yr) is the time it takes for half of it to decay.
After one half-life, half (50 %) of the original amount will remain.
After a second half-life, half of that amount (25 %) will remain, and so on.
We can construct a table as follows:
No. of Fraction Mass
half-lives t/yr Remaining Remaining/g
0 0 1
1 5.3 ½
2 10.6 ¼
3 15.9 ⅛ 40.0
4 21.2 ¹/₁₆
We see that 40.0 g remain after three half-lives.
This is one-eighth of the original mass.
The mass of the original sample was 8 × 40 g = 320 g
Answer:
Atomic Mass
Explanation:
it is also sometimes below the symbol of the element :)
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