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dolphi86 [110]
3 years ago
12

Reaction 1: c3h8(

Chemistry
1 answer:
77julia77 [94]3 years ago
7 0
I don't know this way but as soon as I get there so I will give it to you ok
You might be interested in
When 2.5 grams react, the will produce how many grams of reactant in a complete chemical reaction?
const2013 [10]

Answer:

2.5g

Explanation:

When the reaction goes into completion, they will produce 2.5g. This is complement the law of conservation of mass.

According to the law of conservation of mass "in a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

  • The mass of reactants and products in a chemical reaction must be the same.
  • There is no change in mass in moving from reactant to product
  • So, if we start with 2.5g of reactants, we must end with 2.5g of products.
5 0
3 years ago
A chemical reaction produces formaldehyde, with a chemical formula of CH2O. Carbon is in group 4A, Oxygen is in group 6A, and Hy
steposvetlana [31]

Answer:

Explanation:

carbon in  group 4A needs 4 more electrons to be stable

hydrogen in group 1A has one electron needs 1 more t o be stale

oxygen in group 6A has 6 and needs 2 more to be stable

They all obtain this by sharing electrons  8 around C &O, 2 around H

H  : C:  H

       ::        

      :O:

5 0
2 years ago
The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J
Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

<em>Ea = 16,7 kJ/mol</em>

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

<em>A = 1,13x10¹⁰</em>

<em></em>

I hope it helps!

6 0
3 years ago
The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Otrada [13]

Answer:

25.2 kJ

Explanation:

The complete question is presented in the attached image to this answer.

Note that, the heat gained by the 2.00 L of water to raise its temperature from the initial value to its final value comes entirely from the combustion of the benzoic acid since there are no heat losses to the containing vessel or to the environment.

So, to obtained the heat released from the combustion of benzoic acid, we just calculate the heat required to raise the temperature of the water.

Q = mCΔT

To calculate the mass of water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat capacity of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

From the graph,

Final temperature of water = 25°C

Initial temperature of water = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

6 0
3 years ago
PLS HELP!!
Gnesinka [82]

Answer:

from the 1st equation:

  4NH3                  4NO

  4 *(68)                 4*30

  1216                     X  mass of NO = 536.5 g

from the 2nd Equation

  2NO           2NO2

   2*30            2* 46

   536.5          x         mass of NO2 = 822.6 grams

from the 3rd Equation

  3NO2                         2HNO3

   3*(46)                           2* (63)

     822.6                             X                mass of nitric acid = 751.06 gram

b)  % yields = ( 96.2%* 91.3% *91.4%)= 80.3%

3 0
3 years ago
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