Molar mass :
NH₃ = 17.0 g/mol
(NH₄)₂SO₄ = 132 g/mol
2 NH₃ + H₂SO₄ = (NH₄)₂SO₄
2 x 17 g NH₃ ------------ 132 g <span> (NH</span>₄)₂SO<span>₄
</span>( mass NH₃) ------------ 1.90 x 10⁵ <span> (NH</span>₄)₂SO<span>₄
( mass NH</span>₃) = (1.90 x 10⁵) x 2 x 17 / 132
<span>
( mass NH</span>₃) = 6460000 / 132
<span>
( mass NH</span>₃) = 48939.39 g
<span>
in kg :
48939.39 / 1000 = 48.93 kg = 4.893 x 10</span>¹ kg
<span>
hope this helps!
</span><span>
</span>
Answer:
the oxidation number is 4
Answer:
Explanation:
SO in order to calculate the specific latent heat of fusion, you need to remember the formula:
Where 
representes the specific latent heart of fusion.
represents the heat energy added, usually represented in kJ
represents the mass of the object, in kg.
Now that we have our formula we just have to put our values into the formula:
SO our answer would be
Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
