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34kurt
2 years ago
5

All of the following statements about solutions are correct Except?

Chemistry
1 answer:
Tasya [4]2 years ago
4 0

Answer:

A solution is a heterogeneous mixture

Explanation:

This statement that a solution is a heterogeneous mixture is completely and totally wrong.

A solution is a homogeneous mixture.

Homogeneous mixtures have their constituents existing in just one phase.

  • It is a homogeneous mixture of solutes and solvents.
  • In a solution, the solutes particles are distributed uniformly in the solvent.
  • The solute is the substance that is dissolved to make the solution.
  • Solutes are usually present in a small amount than the solvent.
  • The solvent acts as the dispersing medium which allows the solute to go into the solution.
  • The solute can be solid, liquid or gas.
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What is the mass of 3.8 × 1024 atoms of argon (Ar)?
gulaghasi [49]
40 g Ar.......6.023*10^23 atoms
x g Ar.......3.8*10^24 atoms
x=40*3.8*10^24/(6.023*10^23)=252,365g Ar
6 0
3 years ago
Is a ph = 7.00 solution acidic, basic, or neutral at 37 °c?
rosijanka [135]
I think it is neutral 
8 0
3 years ago
Which of the following is an example of convection?
blsea [12.9K]
Hot air rising and cooler air falling.
5 0
2 years ago
This green solution of chromium(III) can further be reduced by zinc metal to a blue solution of chromium(II) ions. Write the bal
Contact [7]

Answer:

Half-reactions:

Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻

Net ionic equation:

2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺

Explanation:

The Cr³⁺ is reduced to Cr²⁺:

<h3>Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>

Zn is oxidized to Zn²⁺:

<h3>Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-</h3>

Twice the reduction of Cr:

2Cr³⁺ + 2e⁻ → 2Cr²⁺

Now this reaction + Oxidation of Zn:

2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻

<h3>2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation</h3>

6 0
2 years ago
Valence Bond theory predicts that tin will use what hybrid orbitals in Snf5 -1​
LUCKY_DIMON [66]

Answer:

sp3d

Explanation:

The ground state electronic configuration of tin is written as; [Kr] 5s²4d¹⁰5p². Hybridization is a concept used to explain the combination of orbitals of appropriate energy to produce suitable orbitals that could be used for bonding.

In forming the compound Snf5^ -1, we have to hybridize the following orbitals on tin; 5p, 5d and 6s orbitals. This gives us a set of sp3d hybrid  hence the answer.

6 0
2 years ago
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