Which vector points in the direction of the centripetal acceleration of the plane

Physics

1 answer:

MariettaO [177]2 years ago

3 0

The answer is vector D towards the centre.

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A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process have protons been add

AlladinOne [14]

Answer: A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process electrons been removed from it.

Explanation:

It is known that for every atom the protons and neutrons reside in the nucleus of the atom. Whereas electrons move outside the nucleus of an atom. As a result, electrons are able to transfer more easily from one substance to another as compared to the protons.

This is because protons are tightly held by the nucleus of an atom. Whereas electrons are mobile in nature and hence, they can easily move.

Therefore, positive charge on the glass develops due to the removal of electrons from it.

thus, we can conclude that in the given process electrons been removed from the glass object.

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TEA [102]

No air conditioning, I already don’t have it, I only have heating :(

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What year did Badminton become a full-medal Olympic sport?

Basile [38]

Answer:

1992

Explanation:

Badminton made its debut as a demonstration sport at the 1972 Olympic Games in Munich. It was not until the 1992 Games in Barcelona that it was officially included on the Olympic programme, with men's and women's singles and doubles events.

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A light bulb has a voltage of 36 and a current of 8 A. Calculate the resistance of the light bulb

timurjin [86]

R = U : I. U is in Voltage and I is in Ampère. That gives you R = 36 : 8 = 4,5 Ohm

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Charge is distributed uniformly on the surface of a large flat plate. the electric field 2 cm from the plate is 30 n/c. the elec

AysviL [449]

The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
$E= \frac{\sigma}{2\epsilon_0}$
where
$\sigma$ is the charge density
$\epsilon_0$ is the vacuum permittivity

We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
$E=30 N/C$

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