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xenn [34]
3 years ago
9

Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa

rated by 0.455 m on a wall, 1.62 m from the grating, calculate the wavelength of the laser light.

Physics
1 answer:
WINSTONCH [101]3 years ago
3 0

.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

y=0.455m

And the distance between screen abnd grating is,

L=1.62 m

Now the angle can be find as,

tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62})  \\\theta=15.68^{\circ}

Now the grating distance is,

d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m

Now with m=1 condition will become,

\lambda=dsin\theta

So,

\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm

Therefore the wavelength of laser light is 491.4 nm.

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They ask for the transition from the first excited state n = 2 to the base state n = 1

       E₂ - E₁ = = (h² / 8mL²) (n₂² - n₁²)

Let's calculate

       E₂-E₁ = (6.63 10⁻³⁴)² / (8 9.1 10⁻³¹ (0.7 10⁻⁹)²) (2² -1²)

       E₂ –E₁ = 3.6968 10⁻¹⁹ J

Let's use the Planck equation

      E = h f

      c = λ f

      E = h c / λ

      E = E₂ ₂- E₁

      h c / λ  = 3.6968 10⁻¹⁹

      λ  = h c / (E₂-E₁)

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Let's reduce

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      λ  = 538.0 nm

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4 years ago
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