Answer:
W = 1418.9 J = 1.418 KJ
Explanation:
In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:
W = F.d
W = Fd Cosθ
where,
W = Work Done = ?
F = Force = 151 N
d = distance covered = 10 m
θ = Angle with horizontal = 20°
Therefore,
W = (151 N)(10 m) Cos 20°
<u>W = 1418.9 J = 1.418 KJ</u>
Frictional force always opposes applied force, so the net force on the cart would have to be 19N - 1.7N. The acceleration can then be solved by using the relation: F = ma. This is shown below:
Net force = 19 - 1.7 = 17.3 N
Acceleration = Force / mass
Acceleration = 17.3 / 2
Acceleration = 8.65 N/m
Answer:
11.23%
Explanation:
Lets take
Speed of man in still water =u= 1.73 m/s
Speed of flow of water = v=0.52 m/s
When swims in downward direction then speed of man = u + v
When swims in upward direction then speed of man = u - v
Lets time taken by man when he swims in downward direction is
and when he swims in downward direction is
Lets distance is d and it will be remain constant in both the case




Time taken in still water
2 d= t x 1.73
t=1.15 x d sec


total time in current = 0.82 +0.44 d=1.26 d sec
So the percentage time

Percentage time =11.32%
So it will take 11.32% more time as compare to still current.
Answer:

Explanation:
<u>Displacement Vector</u>
Suppose an object is located at a position

and then moves at another position at

The displacement vector is directed from the first to the second position and can be found as

If the position is given as magnitude-angle data ( z , α), we can compute its rectangular components as


The question describes the situation where the initial point is the base of the mountain, where both components are zero

The final point is given as a 520 m distance and a 32-degree angle, so


The displacement is

Answer:
They conduct thermal energy from inside the house and release it outside the house. ... It reduces the amount of thermal energy that is transferred from outside to inside the container