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Finger [1]
3 years ago
10

Jupiter contains a number of small moons that are thought to be captured comets or material ejected by collisions with larger ob

jects. what is the evidence for this theory?
Physics
1 answer:
-Dominant- [34]3 years ago
7 0

I believe the evidence for this theory is that:

The orbits surrounding Jupiter are highly elliptical which are off the plane of the ecliptic, and many of these moons are retrograde. This is very unlikely for moons or satellites which are formed during the planetary accretion. Hence comes the theory.

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The motorcycle travels with a constant speed v0 along the path that, for a short distance, takes the form of a sine curve. Deter
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Let at any instant of time the speed is vo and the angle made by the bike with the horizontal is given

now we have

component of speed in x direction given as

v_x = v_0cos\theta

component of speed in y direction will be

v_y = v_0sin\theta

now from above two equations we can say that here

\theta = angle with the horizontal at any instant

and since here it is a sine curve so we know that

y = sin(x)

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the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ
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D. Increases from pole to equator

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Candice is examining a cell under a microscope. She has identified a cell wall, a nucleus, and a chloroplast. What type of organ
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The US Environmental Protection Agency issues a daily report for pollution levels called the __________.
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Read 2 more answers
A circular radar antenna on a Coast Guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 GHz. Two small boats
Anna35 [415]

Answer:

d = 76.5 m

Explanation:

To find the distance at which the boats will be detected as two objects, we need to use the following equation:

\theta = \frac{1.22 \lambda}{D} = \frac{d}{L}

<u>Where:</u>

θ: is the angle of resolution of a circular aperture

λ: is the wavelength

D: is the diameter of the antenna = 2.10 m

d: is the separation of the two boats = ?

L: is the distance of the two boats from the ship = 7.00 km = 7000 m

To find λ we can use the following equation:

\lambda = \frac{c}{f}

<u>Where:</u>

c: is the speed of light = 3.00x10⁸ m/s

f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz

\lambda = \frac{c}{f} = \frac{3.00 \cdot 10^{8} m/s}{16.0 \cdot 10^{9} s^{-1}} = 0.0188 m            

Hence, the distance is:

d = \frac{1.22 \lambda L}{D} = \frac{1.22*0.0188 m*7000 m}{2.10 m} = 76.5 m

Therefore, the boats could be at 76.5 m close together to be detected as two objects.

 

I hope it helps you!

7 0
3 years ago
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