A. Describe the mass, charge, and location of protons, neutrons, and electrons in an atom.

2 answers:

3 0

A.) i.) Mass of Proton is slightly lower than the neutron and electrons are too lighter as compared to them.

ii.) Proton has positive charge, Electron with negative, and neutrons does not have any charge.

iii.) Proton and Neutron resides under the nucleus so known as "Nucleons" whereas electrons revolve around the nucleus.

B.) Protons and Neutrons determine the atomic mass of an atom, and protons and electrons determine the charge upon it. They are the basic properties and many chemical predictions could be made by this information.

Hope this helps!

serg [7]3 years ago

3 0

A. mass of proton is slightly lower than the neutron and electrons are too lighter as compared to them.

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What is the average velocity of a person walking to the store as

Vlad [161]

Answer:

a=5m/s

Explanation:

V= s/t

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3 years ago

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The space shuttle releases a satellite into a circular orbit 630 km above the Earth.

solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

$\displaystyle g=\frac{GM}{r^2}$

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}$

Remove units to make the equation easier to read.

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Multiply the numerator out.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Add the terms in the denominator.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}$

Simplify this equation.

$\displaystyle g=8.11045189 \ \frac{m}{s^2}$

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

$\displaystyle a = \frac{v^2}{r}$

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.