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3 years ago

A. Describe the mass, charge, and location of protons, neutrons, and electrons in an atom.

2 answers:

3 0

A.) i.) Mass of Proton is slightly lower than the neutron and electrons are too lighter as compared to them.

ii.) Proton has positive charge, Electron with negative, and neutrons does not have any charge.

iii.) Proton and Neutron resides under the nucleus so known as "Nucleons" whereas electrons revolve around the nucleus.

B.) Protons and Neutrons determine the atomic mass of an atom, and protons and electrons determine the charge upon it. They are the basic properties and many chemical predictions could be made by this information.

Hope this helps!

serg [7]3 years ago

3 0

A. mass of proton is slightly lower than the neutron and electrons are too lighter as compared to them.

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The equation that relates two poles to the force between them and their separation is the ____ square law.

Ivenika [448]

A-exponential
You welcome

4 0

2 years ago

The charges and coordinates of two charged particles held fixed in the xy plane are: q1 = +3.3 µc, x1 = 3.5 cm, y1 = 0.50 cm, an

Readme [11.4K]

1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is
$d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$
substituting the coordinates of the two charges, we get
$d= \sqrt{(3.5+2)^2+(0.5-1.5)^2}=5.6~cm=0.056~m$

2) Then, we can calculate the electrostatic force between the two charges $q_1$ and $q_2$ , which is given by
$F=k_e \frac{q_1 q_2}{d^2}$
where $k_e=8.99\cdot10^{9} Nm^2C^{-2}$ is the Coulomb's constant.
Substituting numbers, we get
$F=8.99\cdot10^{9} Nm^2C^{-2} \frac{(3.3\cdot10^{-6}~C) (-4\cdot10^{-6}~C)}{(0.056~m)^2} =-37.8~N$
and the negative sign means the force between the two charges is attractive, because the two charges have opposite sign.

7 0

3 years ago

A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg

Dahasolnce [82]

Answer:

The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

Explanation:

Momentum before = momentum after

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(5 kg) (6 m/s) + (4 kg) (-5 m/s) = (5 kg) v₁ + (4 kg) v₂

10 m/s = 5 v₁ + 4 v₂

Assuming an elastic collision, kinetic energy is conserved.

½ m₁ u₁² + ½ m₂ u₂² = ½ m₁ v₁² + ½ m₂ v₂²

m₁ u₁² + m₂ u₂² = m₁ v₁² + m₂ v₂²

(5 kg) (6 m/s)² + (4 kg) (-5 m/s)² = (5 kg) v₁² + (4 kg) v₂²

280 m²/s² = 5 v₁² + 4 v₂²

Substituting:

v₂ = (10 − 5 v₁) / 4

280 = 5 v₁² + 4 [(10 − 5 v₁) / 4]²

280 = 5 v₁² + (10 − 5 v₁)² / 4

1120 = 20 v₁² + (10 − 5 v₁)²

1120 = 20 v₁² + 100 − 100 v₁ + 25 v₁²

0 = 45 v₁² − 100 v₁ − 1020

0 = 9 v₁² − 20 v₁ − 204

0 = (9 v₁ + 34) (v₁ − 6)

v₁ = -3.78 m/s or 6 m/s

u₁ = 6 m/s, so v₁ = -3.78 m/s. Solving for v₂:

v₂ = (10 − 5 v₁) / 4

v₂ = 7.22 m/s

The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

6 0

3 years ago

If a car is traveling forward at 15 m/s, how fast will it be going in 1.2 seconds if the acceleration is

Law Incorporation [45]

Answer:

Explanation:

v = v⁰ (its original speed) + a (negative acceleration) X t² (time)

v = 15 - 10 x 1.2 = 15 - 12 = 3 (it's slowing down)

3 0

1 year ago

A commuter train travels from New York to Washington, DC, and back in 6 hours and 5 minutes. The distance between the two statio

vovikov84 [41]

Answer:

The train's displacement is zero.

Explanation:

Given data,

The time taken by the train from NY to Washington and back is, t = 6 h 5 min

The distance between the two stations is, d = 363 km

Therefore, the total distance the train traveled is, d' = 726 km

The displacement is defined as the change in position coordinates with respect to its original position.

If the train travels from one point and returns back to the same point after some time, there is no change in the position coordinates with respect to its original position.

Hence, the train's displacement is zero.

3 0

3 years ago