Answer:
Explanation:
formula for the period of a satellite = 2π.
period of satellite A (Ta) = 2π.
period of satellite B (Tb) = 2π.
ratio of the periods of the satellites = (take note that π is shown as )
where
- Me = mass of the earth
- G = universal gravitational constant
- π = 3.142
- all the above are constants and cancel each since they are both at the numerator and denominator
- R = distance from the earth
the equation now becomes
=
- the velocity of a satellite = (take note that π is shown as )
- rearranging the above R = (take note that π is shown as )
- now substituting the above into the equation we have
= (take note that π is shown as )
2π will cancel itself from the numerator and denominator and we have
=
squaring both sides we have
=
now cross multiplying we have
from the question the velocity of satellite A is 3 times that of satellite B hence Va = 3Vb
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
(1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,
while the distance between the first and the fifth minima is
(2)
If we use the formula to rewrite
, eq.(2) becomes
Which we can solve to find a, the width of the slit:
El kilogramo de fuerza, o kilopond, es una unidad de fuerza métrica gravitacional. Es igual a la magnitud de la fuerza ejercida sobre un kilogramo de masa en un campo gravitatorio de 9.80665 m / s².