Answer : The correct option is, C.
Explanation :
pH meter : It is an electric device which measure the concentration of hydrogen-ion in the solution. It also measure the acidity or alkalinity of water in the solution.
Therefore, the purpose of student for testing the lake water is to understand how people use it in their daily-life. As this will help him to analyse the quality of lake water whether, it is fit for use or not.
M(H₂O) = 97,2 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 97,2 g ÷ 18 g/mol.
n(H₂O) = 5,4 mol.
N(H₂O) = n(H₂O) · Na.
N(H₂O) = 5,4 mol · 6,023·10²³ 1/mol.
N(H₂O) = 3,25·10²⁴ molecules of water.
n - amount of substance.
Na - Avogadro number.
Answer:
4804.5 g of SO₂ are needed to the reaction
Explanation:
The reaction to produce sulfuric acid is:
2SO₂ + O₂ + 2H₂O → 2H₂SO₄
Ratio is 1:2. 1 mol of oxygen needs 2 moles of sulfur dioxide in order to react. We can propose this rule of three.
If 1 mol of O₂ react to 2 moles of SO₂
Then, 37.50 moles of O₂ will react with (37.5 . 2) /1 = 75 moles of SO₂
We convert the moles to mass, to know the answer:
75 mol . 64.06 g / 1 mol = 4804.5 g of SO₂
Answer:
The answer to your question is: [H+] = 0.0016
Explanation:
Data
pH = 2.8
[H+] of the solution = ?
Formula
pH = -log [H+]
process
2.8 = -log [H+] then we get antilog
antilog (-2.8 ) = [H+]
[H+] = 0.0016
E=hv
h = 6.626 × 10^-34 joule·s
v=frequency
i got 4.7636x10^-30 J
