Answer:
(a) number of strands (n) = time (t) ÷ proportionality constant (k)
(b) The time needed for the bacterial to double its initial size is 3.36 hours.
Explanation:
(a) Let the rate (time) be represented by t and the amount (number) of strands of bacteria be represented by n
t is proportional to n, therefore, t = kn (k is the proportionality constant)
Since t = kn, then, n = t/k
(b) Initial amount of strands = 300
Amount of strands after 2 hours = 300 + (300 × 20/100) = 300 + 60 = 360
k = t/n = 2/360 = 0.0056 hour/strand
Double of the initial size is 600 (300×2 = 600)
Time (t) needed for the bacterial to double its initial size = kn = 0.0056×600 = 3.36 hours
Stable elements are those which have atleast one isotope with no tendency to "decay", i.e., change into anotherelement.
When stomata are open, carbon dioxide enters the plant through stomata. Carbon dioxide is necessary for the process of photosynthesis in which it is converted together with water into oxygen and glucose. For most plants, it is necessary that stomata are opened during the day when there is a lot of Sunlight also necessary for the process of photosynthesis.
However, some plants from the arid locations have <span>stomata closed during the day, so they reduce water loss that way. In the night when is colder, stomata open and carbon dioxide enters through stomata. </span>
Answer:
C) Scrubbers remove sulfur from the smoke of coal power plants.
Explanation:
Well most scrubbers in North America (U.S) coal plants are used to remove sulfur emissions from coal and lessen the formation of acid rain.
