There are several ways to solve this problem. The easiest one is by trigonometry. I am going to apply this method. If you didn't see trigo yet, I will use the triangles semi equilateral.
Let BD, be the wall on the left and CE on the right (B and D = base of the wall)
1) In Δ BAD, angle BAD = 60°→→ tan (60) =(opposite side)'(adjacent) =BD/DA
tan (60) = 60/DA , but tan (60) = √3 →→√3 = 60/DA or DA = 60/√3
And DA = 34.64
2) In Δ ACE, angle CAE = 30°→→ tan (30) =(opposite side)'(adjacent) =EC/AE
tan (30) = 40/AE , but tan (30) = √3/3 →→√3/3 = 40/AE or AE = (40)/(√3/3)
And AE = 68.28
3) Distance between walls = DA + AE = 34.64 + 68.28 = 103.92
(If you didn't study trigo yet, do let me know then we will solve it with the semi equilateral triangles
Answer:
Rectangle = L x b = 7 x 7 = 49 inch^2
square = a^2 = 2^2=4 inch^2
Therefore the area of rectangle is more because it's area is greater than square
rectangle 's area > square's area.
Answer:
32
Step-by-step explanation:
4*8=32
8+8+8+8=32
4+4+4+4+4+4+4+4=32
A. (-1.15)×3.2 = -(1.15×(3 + .2))
... = -(1.15×3 + 1.15×.2) = -(3.45 + 0.23)
... = -3.68
B. There are two factors in the product, one of which is negative. The total number of negative factors is an odd number, so the product will be negative.
You can also enter the numbers with their signs into a calculator, and it will correctly calculate the sign of the product.
You should have you answer as
X = -8/3