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3 years ago

Item 13 Factor out the coefficient of the variable. The expression 14y+38 factored is

Mathematics

1 answer:

klemol [59]3 years ago

8 0

Answer:

2(7y+19)

Step-by-step explanation:

14y+38=2(7y+19)

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Primitive function for:<br><br> 1. f(x)=4e2x+e−x, sådan att F(0)=2

Free_Kalibri [48]

The primitive function for $f(x) = 4e^{2x} + e^{-x}$ is given by it's indefinite integral.

To calculate it, recall:

$\frac{d}{dx}e^{ax}=ae^{ax}$

$\int c f(x)dx = c\int f(x)dx$

Let's begin

$\int 4e^{2x}+e^{-x}dx \\4\int e^{2x}dx+ \int e^{-x}dx\\4\frac{e^{2x}}{2}+\frac{e^{-x}}{-1} + c\\$

$F(x) = 2e^{2x}-e^{-x} +c$

To find the costant, we just need to use the fact that $F(0)=2$

$F(0) = 2 \\4e^{0}+e^{0} + c =2\\5+c =2\\c=-3$

Therefore,

$\boxed{F(x) = 2e^{2x} - e^{-x} -3 }$

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3 years ago

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3 years ago

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In the diagram, m Find m

IrinaVladis [17]

Find the slope, m, of the line whose graph contains the points (1,2) and (2, 7). ... What does it mean if the slope, m, is negative in y = mx + b?

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How much heat (Btu) is produced by a 150-W light bulb that is on for 20-hours?

rosijanka [135]

Answer:

The heat is produced by a 150-W light bulb that is on for 20-hours is 10200 BTU.

Step-by-step explanation:

To find : How much heat (Btu) is produced by a 150-W light bulb that is on for 20-hours?

Solution :

A 150-W light bulb is on for 20-hours.

The heat produced by bulb is given by,

$H=150\times 20$

$H=3000\ W-hr$

We know that,

$1\ \text{W-hr}=3.4\ \text{BTU}$

Converting W-hr into BTU,

$3000\ \text{W-hr}=3000\times 3.4\ \text{BTU}$

$3000\ \text{W-hr}=10200\ \text{BTU}$

Therefore, The heat is produced by a 150-W light bulb that is on for 20-hours is 10200 BTU.

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4 years ago

16x+40y factor each expression

ira [324]

So find comon factors

factor
16=2 times 2 times 2 times2
40=2 time 2 times 2 times 5
common is
2 times 2 itmes 2=8
reverse distribute
ab+ac=a(b+c)
16x+40y=8(2x+10y)

8(2x+10y)

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3 years ago