<span>50b 50=11b 95 collect the like terms
50b-11b=95-50
39b=45 divide both sides by 39
b=1.2</span>
8(x - 6) = 4x
Distribute.
8x - 48 = 4x
Subtract 8x from both sides.
8x -8x - 48 =4x -8x
Now you have...
-48 = -4x
Divide -4 by both sides.
-48/-4 = -4x/-4
12 = x
The number is 12.
Answer:
8pi feet per second
Or, 25.1 feet per second (3 sf)
Step-by-step explanation:
C = 2pi×r
dC/dr = 2pi
dC/dt = dC/dr × dr/dt
= 2pi × 4 = 8pi feet per second
dC/dt = 25.1327412287
Y=.25x+176.10 Y is the monthly cost and B would be the cost of the insurance every month. X is the amount of miles driven since the .25 stays constant but the amount of miles you drive in a month is different every month, Hence, needs to be a variable that can be adjusted,
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
