Question

What is f(x) = x2 – 8x + 11 written in vertex form? f(x) = (x – 4)2 – 5 f(x) = (x – 4)2 + 5 f(x) = (x + 4)2 – 27 f(x) = (x + 4)2 + 27

Answer 1

Given:

The equation of the function is $f(x)=x^2-8x+11$

We need to determine the vertex form.

Vertex form:

The vertex form of the equation of the parabola can be determined by solving the function $f(x)=x^2-8x+11$ using completing the square method.

The vertex form of the function is of the form $f(x)=a(x-h)^2+k$

We need to write the vertex form of the function in the form of $f(x)=a(x-h)^2+k$

Hence, let us solve the function $f(x)=x^2-8x+11$ using completing the square method.

Thus, we have;

$f(x)=(x^2-8x+16)-5$

$f(x)=(x-4)^2-5$

Thus, the vertex form of the function is $f(x)=(x-4)^2-5$

Hence, Option A is the correct answer.

Answer 2

Answer:

Y= (x - 4) ^2 -5  The answer is A