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KIM [24]
3 years ago
7

Please help me with this!!!

Mathematics
1 answer:
telo118 [61]3 years ago
5 0

Answer:

314 m³

Step-by-step explanation:

The volume (V) of a cone is calculated using the formula

V = \frac{1}{3}πr²h

where r is the radius and h the perpendicular height

To find h use the right triangle from the vertex to the midpoint of the base and the radius.

Using Pythagoras' identity on the right triangle

where the slant height is the hypotenuse, then

h² + 5² = 13²

h² + 25 = 169 ( subtract 25 from both sides )

h² = 144 ( take the square root of both sides )

h = \sqrt{144} = 12, hence

V = \frac{1}{3}π × 5² × 12

   = π × 25 × 4 = 100π ≈ 314 m³

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aliya0001 [1]

Answer:

Refer to the attached file

Hope it helps...

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8 0
3 years ago
A box contains 22 red marbles, 55 green marbles and 55 blue marbles. ​ ​If we choose a marble, then another marble without putti
PSYCHO15rus [73]

Answer:

3025/17292

Step-by-step explanation:

A box contains 22 red marbles, 55 green marbles and 55 blue marbles. ​

The total number of marbles in the box = 22 red marbles + 55 green marbles + 55 blue marbles

= 132 marbles

​If we choose a marble, then another marble without putting the first one back in the box, what is the probability that the first marble will be green and the second will be blue?

This means we are dealing with probability without replacement.

Hence:

P(Green) and P(Blue)

= P(Green) × P(Blue)

= 55/132 × 55/131

= 3025/17292

Therefore, the probability that the first marble will be green and the second will be blue is 3025/17292

7 0
3 years ago
Solve the triangle if B=78 degrees and a=41. Round to the nearest tenth.
padilas [110]

Answer:

b=197.6cm

Step-by-step explanation:

Given that a = 41 and B =78°

From the diagram of the triangle,

Tan θ = opp/adj

Where θ=78°

Tan78°= b/41

b = tan78×41

b = 4.70× 41

b = 197.5944cm

To the nearest tenth

b=197.6cm

3 0
4 years ago
Each side of a square is increasing at a rate of 4 cm/s. at what rate is the area of the square increasing when the area of the
7nadin3 [17]

The question is related to application of derivatives .

Let A represents the area and s represent the side length .

A = s^2

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s =\sqrt{25} = 5

A = s^2

Differentiating both sides with respect to t

It is given that ds/dt = 4cm/s

Substituting the values of s, ds/dt and on multiplying them, we will get

dA/dt = 2(5)(4) = 40 cm^2/s

Therefore rate of change of area when area=25 cm^2 and rate of change of side is 4 cm/s is 40 cm^2/s .

8 0
3 years ago
I don’t understand this one either
IrinaK [193]
If you mirror the shape on the top across the x-axis you get the shape on the bottom. It’s like if you folded it over the horizontal line
4 0
3 years ago
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