Answer:
1.
%K = 31.904%
%Cl = 28.930%
%O = 39.166%
2.
Hg = 80.69/ 200.59 = 0.40/0.2 = 2
S = 6.436/ 32.07 = 0.20/0.2 = 1
O = 12.87/ 16.00 = 0.80/0.2 = 4
Hg2SO4 is the empirical formula
Explanation:
brainliest please?
These are three questions and three complete answers
Answer:
a) Cr²⁺: [Ar] 4s² 3d²
b) Cu²⁺: [Ar] 4s² 3d⁷
c) Co³⁺: [Ar] 4s² 3d⁴
Explanation:
<u>a) Cr²⁺</u>
- Number of elecrons of the neutral atom: 24
- Number of electrons of the ion: 24 - charge = 24 - 2 = 22.
Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....
Hence, for 22 electrons you get:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²
- Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:
[Ar] 4s² 3d²
<u>b) Cu²⁺</u>
- Number of elecrons of the neutral atom: 29
- Number of electrons of the ion: 29 - charge = 29 - 2 = 27.
Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....
Hence, for 27 electrons you get:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷
- Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:
[Ar] 4s² 3d⁷
<u>c) Co³⁺</u>
- Number of elecrons of the neutral atom: 27
- Number of electrons of the ion: 27 - charge = 27 - 3 = 24.
Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....
Hence, for 24 electrons you get:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁴
- Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:
[Ar] 4s² 3d⁴
Answer:
0.43.
Explanation:
In order to solve this question we will need the an equation called Henderson-Hasselbalch Equation. The Henderson-Hasselbalch Equation can be represented by the reaction below;
pH= pKa + log ( [ A^- ] / [ HA] ).
Where HA is the acetic acid and A^- is the Acetate ion
We are given the pH value to be = 4.38 and the ka to be = 1.76×10^–5. So, we will use the value for the ka to find the pKa through the formula below.
pKa = - log ka.
Therefore, pKa = - log( 1.76×10^–5).
pKa= 4.75 + log
So,
4.38 = 4.75 + log ([ A^-] / [HA]).
4.38 - 4.75 = log ( [ A^- ] / [ HA] ).
( [ A^- ] / [ HA] ) = 10^- 0.37.
( [ A^- ] / [ HA] ) = 0.42657951880159265.
( [ A^- ] / [ HA] )= 0.43.
Incomplete question. However, I answered from a general perspective.
<u>Explanation:</u>
Note, a flyer is a piece of advertising leaflet that is usually posted in public spaces, consisting of captivating as well as persuasive message designs. Although there are also digital flyers that can be distributed electronically.
Since in the case we imagine you are a cloth or plastic product manufacturer, your ideal flyer may contain such captions as;
→ with [brand name]
YOUR BEAUTY IS AT ITS BEST!!!
→ LIVE THE MOMENT, EXPRESSION AT WORK!!!
The property by which it can be converted into nuts and bolts
