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uranmaximum [27]
2 years ago
11

A.

Chemistry
1 answer:
Andru [333]2 years ago
7 0

Answer:

Where is the question?

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Three principal models of isostasy are used: 1. The Airy–Heiskanen model – where different topographic heights are accommodated
miss Akunina [59]

Answer:

the answer is B

Explanation:

8 0
2 years ago
Determine the pH of 0.050 M HCN solution. HCN is a weak acid with a Ka equal to 4.9 x 10-10<br> DONE
nadezda [96]

Answer:

The pH of the solution is 5.31.

Explanation:

Let "\alpha is the dissociation of weak acid - HCN.

The dissociation reaction of HCN is as follows.

                  HCN+H_{2}O\rightarrow H_{3}O^{+}+CN^{-}

Initial                  C                         0            0

Equilibrium        c(1- \alpha)              c\alpha c\alpha

Dissociation constant = Ka= c\alpha \times \frac{c\alpha}{c(1-\alpha)}

=\frac{c\alpha^{2}}{(1-\alpha)}

In this case weak acids \alpha is very small so, (1-\alpha ) is taken as 1.

Ka=C\alpha^{2}

\alpha=\sqrt\frac{ka}{c}

From the given the concentration = 0.050 M

Substitute the given value.

\alpha=\sqrt\frac{4.9\times 10^{-10}}{0.05}=9.8\times 10^{-4}

[H_{3}O^{+}]=c\alpha

[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}

pH= -log[H_{3}O^{+}]

=-log[4.9\times10^{-6}]

=6-log 4.9= 5.31

Therefore, The pH of the solution is 5.31.

7 0
3 years ago
Read 2 more answers
For each balanced reaction, indicate the total number of atoms in the table below.
Afina-wow [57]

(i) Make ammonia number of atoms on reactant side is 8 and on product side is 8. (ii) Separate water number of atoms on reactant side is 6 and on product side is 6. (iii) Combust methane number of atoms on reactant side is 9 and number of atoms on product side is 9.  

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

(i) Make Ammonia

First we have to write the balanced chemical equation

             N₂ + 3H₂ → 2NH₃

Reactant side              Product side

N = 2                             N = 2

H = 6                             H = 6

So total number of atoms on product and reactant side is 8.

(ii) Separate Water

First we have to write the balanced chemical equation

            2H₂O → 2H₂ + O₂

Reactant side              Product side

H = 4                             H = 4

O = 2                             O = 2

So total number of atoms on product and reactant side is 6.

(iii) Combust methane

First we have to write the balanced chemical equation

       CH₄ + 2O₂ → 2H₂O + CO₂

Reactant side              Product side

C = 1                             C = 1

H = 4                            H = 4

O = 4                            O = 4

So total number of atoms on product and reactant side is 9.

Thus from the above conclusion we can say that For each balanced reaction, the total number of atoms are

Reaction                            Total number of atoms

                                     Reactant side           Product side

Make Ammonia                   8                               8

Separate Water                   6                               6

Combust Methane              9                               9

Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: For each balanced reaction, indicate the total number of atoms in the table below.

Reaction                            Total number of atoms

                                     Reactant side           Product side

Make Ammonia            _________              __________

Separate Water            _________              __________

Combust Methane       _________              __________

3 0
2 years ago
The equilibrium constant, Kc, for the following reaction is 4.76×10-4 at 431 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
soldier1979 [14.2K]

Answer:

Explanation:

Step 1: Data given

The equilibrium constant, Kc, for the following reaction is 4.76 * 10^-4 at 431 K

The equilibrium concentration of Cl2(g) is  0.233 M

Step 2: The balanced equation

PCl5(g)  ⇄ PCl3(g) + Cl2(g)

Step 3: The initial concentration

[PCl5]= Y M

[PCl] = 0M

[Cl2] = 0M

Step 4: Calculate the concentration at equilibrium

[PCl5] = Y + X M = Y - 0.233 M

[PCl]= XM = 0.233 M

[Cl2]= XM = 0.233 M

Step 5: Define Kc

Kc =  [Cl2]* [PCl3] / [PCl5]

4.76 * 10^-4 = 0.233² / (Y -0.233)

0.000476 = 0.05429 / (Y - 0.233)

Y - 0.233 = 0.05429 / 0.000476

Y - 0.233 = 114.05 M

Y = 114.283 M = the initial concentration

The concentration of PCl5 at the equilibrium is 114.05 M

8 0
3 years ago
A(n) ___ root is a root that is introduced into an equation in the process of solving the equation but does not satisfy the cond
Leto [7]

Answer:

An Extraneous root

Explanation:

A(n) Extraneous root is a root that is introduced into an equation in the process of solving the equation but does not satisfy the conditions of the original equation.

8 0
3 years ago
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