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AleksandrR [38]
3 years ago
10

use the elimination method to solve the system of equations.choose the correct ordered pair. -3y=x-5 x+5y=7. ​

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

<h2>B. (2, 1)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}-3y=x-5&\text{subtract x from both sides}\\x+5y=7\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-x-3y=-5\\x+5y=7\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad2y=2\qquad\text{divide both sides by 2}\\.\qquad\qquad y=1\\\\\text{Put the value of y to the second equation:}\\x+5(1)=7\\x+5=7\qquad\text{subtract 5 from both sides}\\x=2

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Find two positive numbers a and b (witha≤b) whose sum is 88 and whose product is maximized.
Allushta [10]

a + b = 88 <span>
<span>
</span><span>ab = y
</span><span>
</span><span>a = 88 - b
</span><span>
</span><span>y = (88 - b)*b
</span> <span>y = -b^2 + 88b
</span><span>
</span><span>Take the derivative and set equal to 0
</span><span>
</span><span>y' = -2b + 88 = 0
</span><span>
</span><span>2b = 88
</span> <span>b = 44 </span></span>

<span><span>a=44</span></span>

<span><span> both numbers are 44</span></span>

3 0
3 years ago
15 points!
Phantasy [73]

Hi there! You are provided with two points, this is all you need to calculate the line's slope.


The equation for slope is:

\frac{y2 - y1}{x2 - x1}

\frac{10 - 8}{3 - 7} = -\frac{2}{4}

Slope: -2/4


Point slope form, or y-y1 = m(x - x1). All we have to do is take the x and y coordinates of either point, as well as the slope, and plug them into the equation.

y - 10 = -2/4(x - 3)


Write the equation in slope-intercept form (y=mx+b)

y - 10 = -2/4(x-3)\\y = -2/4(x-3) + 10\\y = -2/4x + 1.5 + 10\\y = -2/4x + 11.5


A) -2/4

B) y - 10 = -2/4(x - 3)

C) y = -2/4x + 11.5

8 0
2 years ago
Multiply out -6(2x-8)
Aleksandr-060686 [28]
It would be :
-12 + 48

hope this helps you
6 0
2 years ago
Fx) = x2 - 8x + 15<br> g(x) = x-3<br> h(x) = f(x)/g(x)
aev [14]

Answer: \Large\boxed{h(x)=x-5}

Step-by-step explanation:

\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppp\displaystyle\ \Large \boldsymbol{} h(x)=\frac{f(x)}{g(x)} =? \\\\\\f(x)=x^2-8x+15\\\\\\x^2-8x+\underbrace{15+1-1}_{15}=0 \\\\\\\underbrace{x^2-8x+16}_{(x-4)^2}-1=0 \\\\\\(x-4)^2-1\Longrightarrow f(x)=(x-5)(x-3)                                                     \displaystyle\ \Large \boldsymbol{} h(x)=\frac{(x-3)(x-5)}{(x-3)}=\boxed{x-5}                                          

8 0
2 years ago
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