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vichka [17]
2 years ago
13

The length of the tunnel is 460 miles. If 1 inch represents 60 miles, what is the length of the scale drawing of the tunnel? Rou

nd to the nearest hundredths. Be sure to include units.
Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
4 0

Answer:

7.66 inches

Step-by-step explanation:

In order to find the answer, you need to first find the ratio of miles to inches. You would do this by doing 460/60. In result you would have 7.66.

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What is the y intercept of (-4,6) and (1,-9)​
vladimir1956 [14]

Answer:

what is the y intercept of (-4,6) and (1,-9)​ : (3,-12)

Step-by-step explanation:

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3 years ago
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What are the domain, range, and asymptote of h(x) = (0.5)^x -9
Gala2k [10]

Answer:

Domain- Interval Notation:

( − ∞ , ∞ )

Set-Builder Notation:

{ x | x ∈ R }

Range- Interval Notation:

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{ y | y > − 9 }

Step-by-step explanation:

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3 years ago
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

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Answer:

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