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Sliva [168]
3 years ago
10

Sum of (4x^4-x2-x)+(x^4+x^3+x^2+x-1)

Mathematics
2 answers:
Flauer [41]3 years ago
6 0
<span>                -9x4 + 5x2 - 26x - 12
—————————————————————
                                3

</span>
Sedaia [141]3 years ago
6 0
<span>(4x^4-x2-x)+(x^4+x^3+x^2+x-1)
=</span><span>4x^4 - x2 - x + x^4 + x^3 + x^2 +  x- 1
=5x^4 </span>+ x^3 - 1

(x^2 and x are canceled out)...
x^2 - x^2 = 0
x -x =0
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To find the hypotenuse, let us use the pythagoras theorem,

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Now, substituting these values in the formula for sin 2x, we get,

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Thus, the value of sin(2x) is \frac{120}{169}

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