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Ksenya-84 [330]
3 years ago
5

What is the bond order of c2−?express the bond order numerically?

Chemistry
2 answers:
diamong [38]3 years ago
6 0
MO Diagram of C₂⁻ is shown below, 

Bond order is calculated as,

             Bond Order  =  [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,

BMO  = Bonding Molecular Orbital

ABMO  =  Anti-Bonding Molecular Orbital

Putting values,

             Bond Order  =  [9]-[4] / 2

             Bond Order  =  5 / 2

             Bond Order  =  2.5

Sliva [168]3 years ago
6 0

The bond order of C2− is 1/2 x [m of e- in bonding MO's - n of e- in antibonding MO's]

<h3>Explanation: </h3>

What is the bond order of C2−? express the bond order numerically?

The bond order is a measurement of the number of electrons involved in bonds between two atoms in a molecule. The higher the bond order, the stronger the chemical bond. bond order is equal to the number of bonds between two atoms.

In the case of C2 in a Covalent Bond between two atoms, a single bond has a bond order of one, a double bond has a bond order of two, a triple bond has a bond order of three, and so on

Bond order = 1/2 x [m of e- in bonding MO (Molecular Orbital)'s - n of e- in antibonding MO's]  

Molecular orbital (MO) itself is a mathematical function describing the wave-like behavior of an electron in a molecule. Antibonding orbital is type of molecular orbital (MO) that weakens the chemical bond between two atoms, whereas bonding orbital is used in molecular orbital (MO) theory to describe the attractive interactions between the atomic orbitals of two or more atoms in a molecule.

Thus the bond order of C2^- is 1/2 x (9-4) = 2.5  

The bond order of C2− is paramagnetic because it has an odd electron

Learn more about bond order brainly.com/question/7248593

#LearnWithBrainly

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andrey2020 [161]

The options are;

A) The skater experiences acceleration both while skating in a straight line and while making her turn.

B) Because the skater does not change her direction or speed, she does not experience acceleration.

C) The skater only experiences acceleration when she is turning.

D) The skater only experiences acceleration while skating in a straight line.

Answer:

A: The skater experiences acceleration both while skating in a straight line and while making her turn

Explanation:

We are told that She speeds up on the straight portion of the rink. This means that she experienced an acceleration since the speed was not constant but gradually increasing.

Also, we are told that She slows down near each end of the rink and then turns around. This means that she reduced speed before turning and it means there was also an acceleration as well when making the turn.

Thus, she experience acceleration both in the straight line and when making turn.

Option A is correct

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Explanation:

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Answer:

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Now, the farther one gets away from the surface of the earth by climbing a mountain, the further the person is from the Earth's centre of gravity.

We know that the formula for Force of gravity away from the Earth's surface is given by;

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Now, the gravitational force equals the weight of the individual.

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Answer:

We have 1.361 moles in the sample

Explanation:

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To calculate the number of moles we will use following formula:

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