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Ksenya-84 [330]
4 years ago
5

What is the bond order of c2−?express the bond order numerically?

Chemistry
2 answers:
diamong [38]4 years ago
6 0
MO Diagram of C₂⁻ is shown below, 

Bond order is calculated as,

             Bond Order  =  [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,

BMO  = Bonding Molecular Orbital

ABMO  =  Anti-Bonding Molecular Orbital

Putting values,

             Bond Order  =  [9]-[4] / 2

             Bond Order  =  5 / 2

             Bond Order  =  2.5

Sliva [168]4 years ago
6 0

The bond order of C2− is 1/2 x [m of e- in bonding MO's - n of e- in antibonding MO's]

<h3>Explanation: </h3>

What is the bond order of C2−? express the bond order numerically?

The bond order is a measurement of the number of electrons involved in bonds between two atoms in a molecule. The higher the bond order, the stronger the chemical bond. bond order is equal to the number of bonds between two atoms.

In the case of C2 in a Covalent Bond between two atoms, a single bond has a bond order of one, a double bond has a bond order of two, a triple bond has a bond order of three, and so on

Bond order = 1/2 x [m of e- in bonding MO (Molecular Orbital)'s - n of e- in antibonding MO's]  

Molecular orbital (MO) itself is a mathematical function describing the wave-like behavior of an electron in a molecule. Antibonding orbital is type of molecular orbital (MO) that weakens the chemical bond between two atoms, whereas bonding orbital is used in molecular orbital (MO) theory to describe the attractive interactions between the atomic orbitals of two or more atoms in a molecule.

Thus the bond order of C2^- is 1/2 x (9-4) = 2.5  

The bond order of C2− is paramagnetic because it has an odd electron

Learn more about bond order brainly.com/question/7248593

#LearnWithBrainly

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<em>A mixture of nitrogen and neon gas is expanded from a volume of 53.0 L to a volume of 90.0 L, while the pressure is held constant at 71.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.</em>

<em />

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