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djyliett [7]
3 years ago
15

How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL

Chemistry
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

209.98 g of NaOH

Explanation:

We are given;

  • Volume of HCl as 3 L
  • Molarity of HCl as 1.75 M

We are required to calculate the mass of NaOH required to completely neutralize the acid given.

First, we write a  balanced equation for the reaction between NaOH and HCl

That is;

NaOH + HCl → NaCl + H₂O

Second, we determine the number of moles of HCl

Number of moles = Molarity × Volume

                             = 1.75 M × 3 L

                             = 5.25 moles

Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

                          = 5.25 moles

Fourth, we determine the mass of NaOH

Molar mass of NaOH = 39.997 g/mol

Mass of NaOH = 5.25 moles × 39.997 g/mol

                        = 209.98 g

Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl

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The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine: TRUE

<h3>What is the book value?</h3>
  • Book value is the worth of an asset based on its balance sheet account balance in accounting.
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Complete question:

The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine. (Ignore taxes.) TRUE or FALSE

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How many grams of magnesium metal will react completely with 5.2 liters of 4.0 M HCl?
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