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2 years ago

How many moles of HNO₃ will be produced from the reaction of 37.0 g of NO₂ with excess water in the following chemical reaction?

Chemistry

1 answer:

garri49 [273]2 years ago

8 0

Answer:

0.536 mol HNO₃

Explanation:

Step 1: Convert 37.0 g of NO₂ into mol NO₂:

37.0 g NO₂ x 1 mol NO₂/46.0 g NO₂ = 0.8043 mol NO₂

Step 2: Convert 0.8043 mol NO₂ into mol HNO₃:

0.8043 mol NO₂ x 2 mol HNO₃/3 mol NO₂ = 0.5362 mol HNO₃

Step 3: Round to 3 significant figures:

0.5362 mol HNO₃ -> 0.536 mol HNO₃

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Consider the process of diluting 1.2 M NH4Cl solution to prepare 1.4 L of a 0.25 M NH4Cl solution. Determine if each of the foll

stepan [7]

Answer: True the dilution formula is a balanced of mole of the solute..

Explanation:

M1V1 = M2V2

When M1= 1.2M, M2= 0.25M V2= 1.4L and V1= ?

Then V1= 0.25*1.4/1.2

= 0.29

This indicate that 0.29L of the 1.2M NH4Cl will be dilluted to 0.25M in 1.4L of the solution....

The mole number of the solute remain constant

8 0

3 years ago

A mountain climber at the peak of a mountain has _____<br> energy.

hodyreva [135]

Answer:

Potential energy

Explanation:

A mountain climber at the peak of a mountain has potential energy.

The potential energy of a body is stored energy in a body. It is function of mass and position of the body.

Mathematically;

P.E = mgh

m is the mass

g is the acceleration due to gravity

h is the height

7 0

2 years ago

A bar of copper has a mass of 216g and a volume of 24cm^3. What is the density of copper?

7nadin3 [17]

Answer:

<h2>The answer is 9 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 216 g

volume = 24 cm³

The density is

$density = \frac{216}{24} \\$

We have the final answer as

Hope this helps you

3 0

3 years ago

___Fe + ___O2 →___Fe2O3

Ainat [17]

The answer is D or 4,3,2!

3 0

2 years ago

Read 2 more answers

The rate constants of some reactions double with every 10-degree rise in temperature. Assume that a reaction takes place at 295

LUCKY_DIMON [66]

Answer : The activation energy for the reaction is, 51.9 kJ

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at 295 K

$K_2$ = rate constant at 305 K = $2K_1$

Ea = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 295 K

$T_2$ = final temperature = 305 K

Now put all the given values in this formula, we get:

$\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{295K}-\frac{1}{305K}]$

$Ea=51879.96J=51.9kJ$

Therefore, the activation energy for the reaction is, 51.9 kJ

8 0

3 years ago