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lilavasa [31]
3 years ago
13

How many moles of HNO₃ will be produced from the reaction of 37.0 g of NO₂ with excess water in the following chemical reaction?

Chemistry
1 answer:
garri49 [273]3 years ago
8 0

Answer:

0.536 mol HNO₃

Explanation:

Step 1: Convert 37.0 g of NO₂ into mol NO₂:

37.0 g NO₂ x 1 mol NO₂/46.0 g NO₂ = 0.8043 mol NO₂

Step 2: Convert 0.8043 mol NO₂ into mol HNO₃:

0.8043 mol NO₂ x 2 mol HNO₃/3 mol NO₂ = 0.5362 mol HNO₃

Step 3: Round to 3 significant figures:

0.5362 mol HNO₃ -> 0.536 mol HNO₃

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A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to . He'll do this by add
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Answer:

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Explanation:

It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:

" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "

Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.

To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂

Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.

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