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jeyben [28]
3 years ago
12

Apply the distributive property to factor out the greatest common factor.

Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:

1.

90+27

2.

90 = 9 x 10

3.

27 = 9 x 3

4.

So apply the distributive property would be:

90 + 27 = 9(10 + 3)

That would be it i'm sure glad to help

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What is the solution of 4 startroot 5 x 66 endroot = x 10? x = –10 x = 3 x = –10 or x = 3 no solution
eduard

Answer:

x=3

Step-by-step explanation:

....................

4 0
2 years ago
Match each function with the corresponding function formula when h(x)=5-3x and g(x)=-3+5
Grace [21]

Answer:

k(x) = (3g + 5h)(x) ⇒ (1)

k(x) = (5h - 3g)(x) ⇒ (3)

k(x) = (h - g)(x) ⇒ (2)

k(x) = (g + h)(x) ⇒ (4)

k(x) = (5g + 3h)(x) ⇒ (5)

k(x) = (3h - 5g)(x) ⇒ (6)

Step-by-step explanation:

* To solve this problem we will substitute h(x) and g(x) in k(x) in the

  right column to find the corresponding function formula in the

  left column

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

- Lets start with the right column

# k(x) = (3g + 5h)(x)

∵ g(x) = -3^x + 5

∵ 3g(x) = 3[-3^x + 5] = [3 × -3^x + 3 × 5]

- Lets simplify 3 × -3^x

 take the negative out -(3 × 3^x), and use the rule a^n × a^m = a^(n+m)

∴ -3(3 × 3^x) = -(3^x+1)

∴ 3g(x) = -3^x+1 + 15

∵ h(x) = 5 - 3x

∵ 5h(x) = 5[5 - 3x] = [5 × 5 - 5 × 3x] = 25 - 15x

- Now substitute 3g(x) and 5h(x) in k(x)

∵ k(x) = (3g + 5h)(x)

∴ k(x) = -3^x+1 + 15 + 25 - 15x ⇒ simplify

∴ k(x) = 40 - 3^x+1 - 15x

∴ k(x) = 40 - 3^x+1 - 15x ⇒ k(x) = (3g + 5h)(x)

* k(x) = (3g + 5h)(x) ⇒ (1)

# k(x) = (5h - 3g)(x)

∵ 5h(x) = 25 - 15x

∵ 3g(x) = -3^x+1 + 15

∵ k(x) = (5h - 3g)(x)

∴ k(x) = 25 - 15x - (-3^x+1 + 15) = 25 -15x + 3^x+1 - 15 ⇒ simplify

∴ k(x) = 10 + 3^x+1 - 15x

∴ k(x) = 10 + 3^x+1 - 15x ⇒ k(x) = (5h - 3g)(x)

* k(x) = (5h - 3g)(x) ⇒ (3)

# k(x) = (h - g)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (h - g)(x)

∴ k(x) = 5 - 3x - (-3^x + 5) = 5 - 3x + 3^x - 5 ⇒ simplify

∴ k(x) = 3^x - 3x

∴ k(x)= 3^x - 3x ⇒ k(x) = (h - g)(x)

* k(x) = (h - g)(x) ⇒ (2)

# k(x) = (g + h)(x)

∵ h(x) = 5 - 3x

∵ g(x) = -3^x + 5

∵ k(x) = (g + h)(x)

∴ k(x) = -3^x + 5 + 5 - 3x ⇒ simplify

∴ k(x) = 10 - 3^x - 3x

∴ k(x)= 10 - 3^x - 3x ⇒ k(x) = (g + h)(x)

* k(x) = (g + h)(x) ⇒ (4)

# k(x) = (5g + 3h)(x)

∵ g(x) = -3^x + 5

∵ 5g(x) = 5[-3^x + 5] = [5 × -3^x + 5 × 5] = 5(-3^x) + 25

∴ 5g(x) = -5(3^x) + 25

∵ h(x) = 5 - 3x

∵ 3h(x) = 3[5 - 3x] = [3 × 5 - 3 × 3x] = 15 - 9x

- Now substitute 5g(x) and 3h(x) in k(x)

∵ k(x) = (5g + 3h)(x)

∴ k(x) = -5(3^x) + 25 + 15 - 9x ⇒ simplify

∴ k(x) = 40 - 5(3^x) - 9x

∴ k(x) = 40 - 5(3^x) - 9x ⇒ k(x) = (5g + 3h)(x)

* k(x) = (5g + 3h)(x) ⇒ (5)

# k(x) = (3h - 5g)(x)

∵ 3h(x) = 15 - 9x

∵ 5g(x) = -5(3^x) + 25

∵ k(x) = (3h - 5g)(x)

∴ k(x) = 15 - 9x - [-5(3^x) + 25] = 15 - 9x + 5(3^x) - 25 ⇒ simplify

∴ k(x) = 5(3^x) - 9x - 10

∴ k(x) = 5(3^x) - 9x - 10 ⇒ k(x) = (3h - 5g)(x)

* k(x) = (3h - 5g)(x) ⇒ (6)

4 0
3 years ago
Find the value of Z for the triangles
kolbaska11 [484]

Answer:

z = 17.5

Step-by-step explanation:

segment RX is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is

\frac{RS}{RT} = \frac{SX}{TX} , substitute values

\frac{15}{z} = \frac{6}{7} ( cross- multiply )

6z = 105 ( divide both sides by 6 )

z = 17.5

4 0
3 years ago
Laketown had 215 inches of snowfall last year, but only 155 inches this year. What was the percent decrease in snowfall for Lake
skelet666 [1.2K]
Okay, so FIRST you would subtract 215 - 155, which is 60, and THEN divide it by 215, so 60 divided by 215 = 0.27, and rounded that is 0.28, then you move the decimal two places to the right to make it a percentage so your answer would be A., 28%
I hope I helped! =D
8 0
3 years ago
Read 2 more answers
What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?
kvasek [131]

Answer:

The center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

\left(x-a\right)^2+\left(y-b\right)^2=r^2

here,

  • r =  raduis
  • center = (a, b)

Given the equation

\left(x-14\right)^2+\left(y+21\right)^2=64

\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}

\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2

comparing with the circle equation

\left(x-a\right)^2+\left(y-b\right)^2=r^2

Therefore, the center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

7 0
3 years ago
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