The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Answer:
see explanation
Step-by-step explanation:
Using the rules of radicals/ exponents
× 
= 
⇔ ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Simplifying each term
7
= 7
x
= x × 
× 
= x × 3 × 
= 3 × 
= 3
Subtracting the 2 simplified like terms, that is
7 - 3
= 4 ← return to radical form
= 4
<span>To minimize the perimeter you should always have a square.
sqrt(289) = 17
The dimensions should be 17 X 17
To see , try starting at length 1, and gradually increase the length.
The height decreases at a faster rate than the length increases, up until you reach a square.
Or if you want to use algebra, Say the width is 17-x
Then the length is 289/(17-x)
Now, this is bigger than 17+x, as shown here:
289/(17-x) > 17+x
289 > 289 - x^2
which is true.
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17
Again, the dimensions should be a square. 17 X 17.</span>
A
100+89.50×36
=3,322
b
3,322−2,900
=422
c
2,900÷89.50
=33
