Explanation:
The magnet uses electromagnetic induction meaning it can be readily magnetized and demagnetized (using electricity) when required. When electricity is switched on, it becomes magnetized and lifts an object and when electricity is switched off, it loses magnetism and releases the object.
The magnetic is able to lift heavy objects because it has powerful conductor material (ferromagnetic iron) and the number of electromagnetic coils is many to induce a powerful magnetic force. The electric current, inducing the magnetism, is also powerful.
Learn More:
For more on electromagnetic induction check out;
brainly.com/question/3414535
brainly.com/question/13369951
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Answer:
1. B
2. E
3. A
4. D
5. C
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Hope I helped!!!
GL :)
Answer:
2.8 x 10²³ molecules H₂O
1.4 x 10²³ molecules O₂
Explanation:
First, you will need the balanced chemical equation for the formation of water:
2H₂ + O₂ -> 2H₂O
This will help in determining the mole ratios between water and oxygen, which we will need later.
Let's first calculate the number of H₂O (water) molecules. This will require stoichiometry. We are also given the mass, so we must convert mass into moles, then moles into molecules. mass -> moles -> molecules
8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (6.02 x 10²³ molecules H₂O/1 mol H₂O) = 2.8404 x 10²³ molecules H₂O
Rounded to 2 significant digits: 2.8 x 10²³ molecules H₂O
Now, to find the molecules of water, we can begin with the same stoichiometric equation, but before we convert to molecules, we will have to convert moles of water to moles of oxygen. This is where we will use the mole ratio of water to oxygen we got from the balanced chemical equation earlier. 2H₂O:1O₂
8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (1 mol O₂/2 mol H₂O) x (6.02 x 10²³ molecules O₂/1 mol O₂) = 1.4202 x 10²³ molecules O₂
Rounded to 2 significant digits: 1.4 x 10²³ molecules O₂
Answer:
Density rectangular block = 7.47 (Approx) gm/cm³
Explanation:
Given:
Length = 8.335 cm
Width = 1.02 cm
Height = 0.982 cm
Mass = 62.3538 gm
Find:
Density rectangular block
Computation:
Volume of block = lbh
Volume of block = (8.335)(1.02)(0.982)
Volume of block = 8.3486 cm³
Density = Mass / Volume
Density rectangular block = 62.3538 / 8.3486
Density rectangular block = 7.47 (Approx) gm/cm³
