Answer:
see explanation
Step-by-step explanation:
Given
a = ![\left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To obtain -3a multiply each of the elements of a by -3
3a = ![\left[\begin{array}{ccc}-3(3)\\-3(2)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%283%29%5C%5C-3%282%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}-9\\-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-9%5C%5C-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To obtain 1.5a multiply each element by 1.5
1.5a = ![\left[\begin{array}{ccc}1.5(3)\\1.5(2)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1.5%283%29%5C%5C1.5%282%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4.5\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4.5%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
where
is the angle between the vectors. You have
The vectors would be orthogonal if the dot product had been zero, but that's clearly not the case.
They would be parallel if the angle turned out to be
or
, but that's also not the case.
So the answer is neither.
Answer:
HMMMMM
Step-by-step explanation:
9514 1404 393
Answer:
72
Step-by-step explanation:
The triangles are said to be similar. (ΔNPQ ~ ΔRSQ) That means corresponding sides have the same ratio:
NP/RS = NQ/RQ = PQ/SQ = 24/32 = 21/28 = 3/4
This ratio, or scale factor, also applies to the perimeters of the two triangles.
perimeter NPQ / perimeter RSQ = 3/4
Using the given expressions for the perimeters, we have ...
(7x +2)/(10x -4) = 3/4
We can solve this equation in the usual way to find the value of x. Then we can use that value to find the perimeter of ΔNPQ.
4(7x +2) = 3(10x -4) . . . . . multiply both sides by 4(10x -4)
28x +8 = 30x -12 . . . . . eliminate parentheses
20 = 2x . . . . . . . . . . . add 12-28x to both sides
10 = x . . . . . . . . . . . divide both sides by 10
The perimeter of ΔNPQ is ...
7x +2 = 7(10) +2 = 72
The perimeter of triangle NPQ is 72 units.
