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butalik [34]
3 years ago
6

a rectangle measures by 3 cm by 4 cm. a rectangle similar to the first measures 12 cm by 16 cm. find the ratio of the areas of r

ectangles. how does that ratio compare with the ratio of the side lengths?
Mathematics
1 answer:
kumpel [21]3 years ago
6 0
The side that measures 12 cm corresponds to the side that measures 3 cm.
The side that measures 16 cm corresponds to the side that measures 4 cm.
The ratio of the side lengths is (12 cm)/(3 cm) = (16 cm)/(4 cm) = 4

Now let's calculate the two areas.

For the 3 cm by 4 cm rectangle:
A = LW = 3 cm * 4 cm = 12 cm^2

For the 12 cm by 16 cm rectangle:
A = LW = 12 cm * 16 cm = 192 cm^2

The ratio of the areas is (192 cm^2)/(12 cm^2) = 16

The ratio of the areas is 16.
The ratio of side lengths is 4.
Notice that 16 = 4^2.
The ratio of the areas is the square of the ratio of the side lengths.
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3 years ago
I need help quick, its super hard
faltersainse [42]

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Q

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5 0
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The Distributive Property Is Used When You Multiply 3x To (5-2) Which Then Means
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6 0
3 years ago
PLEASE HELP!!! I don't understand it
Len [333]

Answer:

A

Step-by-step explanation:

This is exponential decay; the height of the ball is decreasing exponentially with each successive drop.  It's not going down at a steady rate.  If it was, this would be linear.  But gravity doesn't work on things that way.  If the ball was thrown up into the air, it would be parabolic; if the ball is dropped, the bounces are exponentially dropping in height.  The form of this equation is

y=a(b)^x, or in our case:

A(n)=a(b)^{n-1}, where

a is the initial height of the ball and

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a = 1.5 and

b = .74

Filling in,

A(n)=1.5(.74)^{n-1}

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A(6)=1.5(.22190066)

So the height of the ball is that product.

A(6) = .33 cm

A is your answer

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3 years ago
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