Answer:
a. the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon
Explanation:
F= ma
v²=u² -2aS
(1.56 ✕ 10⁶)²=(2.40 ✕ 10⁶)²-2a(1220)
a=1.36×10⁹m/s²
recall
F=ma
F = 1.88 ✕ 10⁻²⁸ kg × 1.36×10⁹m/s²
F= 2.55 × 10⁻¹⁹N
the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon
F/mg= 2.55 × 10⁻¹⁹/ (1.88 ✕ 10⁻²⁸ × 9.8)
= 1.38 × 10⁸
Answer:
Explanation:
Initial velocity (u) = 2 m/s
Displacement (s) = 2.5 m
Acceleration due to gravity(a)=9.81m/s^2
Final velocity (v) = ?
Now, formula is given by
v² = u² + 2×a×s
v² = 2² + 2×9.81×2.5
v² = 4 + 49.05
v² = 53.05
v = √53.05
v = 7.3 m/s
Answer: 2.13 E 4 J
Explanation: Heat absorbed = mass * specific heat capacity * change in temperature
= 0.5 * 387 * (400 - 290) J
= 0.5 * 387 * 110 J = 21285 J = 2.13 E 4 J
Answer: Not 100% sure but I believe the answer is B.
Hope this helps! ^^