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worty [1.4K]
4 years ago
13

A wire 24 cm long is cut into two pieces. The longer piece is 6 cm longer than the shorter piece.

Mathematics
1 answer:
sattari [20]4 years ago
6 0

Answer:

The size of the shorter piece is 9cm, because 9+(9+6)=24

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If f(1)=3 and f(n)=-2f(n-1)+ 1, then f(5)=
AlladinOne [14]
Our function is f(n)=-2f(n-1)+1.
We want to find f(5).
Let's substitute 5 for n.
f(5) = -2f(5-1) + 1
f(5) = -2f(4) + 1
We need to know f(4).
f(4) = -2f(4-1) + 1
f(4) = -2f(3) + 1
We need to know f(3).
f(3) = -2f(3-1) + 1
f(3) = -2f(2) + 1
We need to know f(2).
f(2) = -2f(2-1) + 1
f(2) = -2f(1) + 1
We know that f(1) = 3
f(2) = -2(3) + 1
f(2) = -6 + 1
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Now we can use f(2) = -5 to find f(3)...
f(3) = -2(-5) + 1
f(3) = 10 + 1
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f(4) = -2(11) + 1
f(4) = -22 + 1
f(4) = -21
Now we can use f(4) = -21 t find f(5)!
f(5) = -2(-21) + 1
f(5) = 42 + 1
f(5) = 43
7 0
3 years ago
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What is the slope of the line through (-4, 2) and (3, -3)?
koban [17]

Answer:

-5/7

Step-by-step explanation:

(-4,2) (3,-3)

-3-2= -5

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How many solutions does the following equation have? 4x+x+3=4x *
kvv77 [185]

Answer:

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Step-by-step explanation:

4x + x + 3 = 4x (Subtract 4x from both sides)

x + 3 = 0 (Subtract 3 from both sides)

x = -3

4 0
3 years ago
The FDA recommends that women who are pregnant avoid eating more than three 6.00 oz servings of bluefish per month because of th
kirza4 [7]

Answer:

5,562 x 10^{-6}

Step-by-step explanation:

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the maximum amount of bluefish per month = 3 * 6.00 oz = 18.00 oz

  • Since bluefish contains <em>0.309 ppm of mercury per 1x10^{6} oz of fis</em>h, then:

0.309 oz mercury --------> 1x10^{6} oz of fish

How many  (y)      --------> 18.00 oz of fish

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5 0
3 years ago
Please help! asap! thank you so much! I have photos attached!
schepotkina [342]

Answer:


Step-by-step explanation:

Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.

We have given here,

a =-2 , b = 3 ,  c = -4 and d = -6

Now we know that An absolute function always gives a positive value.

Let's apply this strategy in the given problems.

1. ║a+b║

Plug a= -2 and b = 3

We get, ║-2+3║=║1║= 1

2. 5║c+b║

Plug c= -4 and b=3

i.e.   5║-4 + 3║= 5║-1║=5×1 = 5

3. a+b║c║

Plug values a= -2 , b=3 and c=-4

i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10

4. ║a+c║÷(-d)

i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1

5. 3║a+d║+b

i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27

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