Answer:
Explanation:
For automobile emission, a uniform standard is preferred, because no unnecessary advantage is given by it to any company that is located in particular states where the regional standards are less severe.
Since pollution has its impact across the states and in the whole of the USA, then there should be uniform standards across all the states. It will also invalidate the impact of regional standards as a factor in the selection of plant locations for the automobile company. It means that a state offering less valid emission standards, will attract more companies to herself and it will be against the other states who care more about the natural environment. It can make more states to opt for the permissive emission standards, that will be more harmful to the USA as a country, than the good. So, a uniform standard is preferred to eliminate it as a factor in plant location decisions.
Yes, uniform standards are beneficial to everyone, because it will bring effective control upon the pollution level because there will be no state where the culprit firm can hide. Besides, it is more effective as efforts done towards environment conservation.
Answer:
The solution code is written in Java.
System.out.println(numItems);
Explanation:
Java <em>println() </em>method can be used to display any string on the console terminal. We can use <em>println()</em> method to output the value held by variable <em>numItems.</em> The <em>numItems </em>is passed as the input parameter to <em>println()</em> and this will output the value of <em>numItems</em> to console terminal and at the same time the output with be ended with a newline automatically.
Answer:
a) 
b)
Explanation:
Given that:
diameter d = 12 in
thickness t = 0.25 in
the radius = d/2 = 12 / 2 = 6 in
r/t = 6/0.25 = 24
24 > 10
Using the thin wall cylinder formula;
The valve A is opened and the flowing water has a pressure P of 200 psi.
So;
b)The valve A is closed and the water pressure P is 250 psi.
where P = 250 psi
The free flow body diagram showing the state of stress on a volume element located on the wall at point B is attached in the diagram below
Answer:
See explaination
Explanation:
#include <iostream>
#include<string.h>
using namespace std;
bool isPalindrome(string str, int lower, int upper){
if(str.length() == 0 || lower>=upper){
return true;
}
else{
if(str.at(lower) == str.at(upper)){
return isPalindrome(str,lower+1,upper-1);
}
else{
return false;
}
}
}
int main(){
string input;
cout<<"Enter string: ";
cin>>input;
if(isPalindrome(input,0,input.length()-1)){
cout<<input<<" is a palindrome"<<endl;
}
else{
cout<<input<<" is NOT a palindrome"<<endl;
}
return 0;
}
The answer is B because it could be feasible but it’s not a need it and you got a time frame but it’s not a requirement and it doesn’t have to be unique.
