Answer:
the lift equation states that lift L is equal to the lift coefficient CI times the density r times half of the velocity V squared times the wing area A. For given air conditions,shape and inclination of the object, we have to determine a value of CI to determine the lift.
Not really sure but this is all I know
Answer:
quality ingredients and exceeding industry standards
Explanation:
Answer:
d. all of these
Explanation:
Electrostatic discharge will generally produce excess voltage in a local area that results in excessive current and excessive heat. It will blast a crater in an MOS device, or melt bond wires, or cause damage of other sorts. In short, MOS devices are subject to damage from "all of these."
Answer:
The work transfer per unit mass is approximately 149.89 kJ
The heat transfer for an adiabatic process = 0
Explanation:
The given information are;
P₁ = 1 atm
T₁ = 70°F = 294.2611 F
P₂ = 5 atm
γ = 1.5
Therefore, we have for adiabatic system under compression

Therefore, we have;

The p·dV work is given as follows;

Therefore, we have;
Taking air as a diatomic gas, we have;

The molar mass of air = 28.97 g/mol
Therefore, we have

The work done per unit mass of gas is therefore;

The work transfer per unit mass ≈ 149.89 kJ
The heat transfer for an adiabatic process = 0.