Answer:
The answer is D.. 2^0
Step-by-step explanation:
i had the same question in my program
Solve for y by setting one equation =to X after that you can substitute the equation into the other one let's set the first one in X= FORM
X-7y=10
-2x+14y=-20
Add 7y to both sides of the first equation to let x stand alone
X=7y+10
Now you can substitute x on the second equation
-2 (7y+10)+14y=-20
Distribute
-14y-20+14y=-20
Add and simplify
Us cancel out =0
-20=-20
0=0
They are the same equations you can also divide the second equation by -2 which would make it look like this
X-7y=10
-2 (x-7y=10)
Let me know if I have answered your question
You start counting from 0 onwards:
C = 6
D = 8
Then C x D = 48
So the product CxD is situated at 48 units from 0
Answer:
- x + y ≤ 600
- 5x +7y ≥ 3500
- it is possible
Step-by-step explanation:
a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.
x + y ≤ 600 . . . . . . . limit imposed by available seating
5x +7y ≥ 3500 . . . . required revenue to meet expenses
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b) For x = 330, the first inequality puts one limit on y:
330 +y ≤ 600
y ≤ 270
And the second inequality puts another limit on y:
5(330) +7y ≥ 3500
7y ≥ 1850 . . . . subtract 1650
y ≥ 264.3 . . . . divide by 7
The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.
