The maximum revenue generated is $160000.
Given that, the revenue function for a sporting goods company is given by R(x) = x⋅p(x) dollars where x is the number of units sold and p(x) = 400−0.25x is the unit price. And we have to find the maximum revenue. Let's proceed to solve this question.
R(x) = x⋅p(x)
And, p(x) = 400−0.25x
Put the value of p(x) in R(x), we get
R(x) = x(400−0.25x)
R(x) = 400x - 0.25x²
This is the equation for a parabola. The maximum can be found at the vertex of the parabola using the formula:
x = -b/2a from the parabolic equation ax²+bx+c where a = -0.25, b = 400 for this case.
Now, calculating the value of x, we get
x = -(400)/2×-0.25
x = 400/0.5
x = 4000/5
x = 800
The value of x comes out to be 800. Now, we will be calculating the revenue at x = 800 and it will be the maximum one.
R(800) = 400x - 0.25x²
= 400×800 - 0.25(800)²
= 320000 - 160000
= 160000
Therefore, the maximum revenue generated is $160000.
Hence, $160000 is the required answer.
Learn more in depth about revenue function problems at brainly.com/question/25623677
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Answer:
We can describe FOIL using the distributive property of multiplication. For real numbers x, y, and z the distributive property of multiplication states that
Now let 
, where v and w are real numbers.
Then 
Here, we can again use the distributive property of multiplication to get
Hence, it follows that
This is the method of FOIL (first: xv, outside: xw, inside: yv, last: yw)
For example, 
Answer:
60
Step-by-step explanation:
You need the least common multiple of 5, 3, and 4.
5 = 5, 10, 15, 20, 25... 60
3= 3, 6, 9...60
4=4, 8, 12, ...60
Answer:
B) Write out the relation in an x-y table and check that each x-value corresponds to the only one x - value
